Books Books
RULE.* To the sum of the areas of the two ends add four times the area of a section parallel to and equally distant from both ends, and this last sum multiplied by £ of the height will give the solidity.
A Treatise on Surveying and Civil Engineering, Wherein Everything that is ... - Page 68
by P. O'Shaughnessy (Civil engineer) - 1848 - 98 pages

## The Architect's and Builder's Pocket-book of Mensuration, Geometry ...

Frank Eugene Kidder - 1892 - 1032 pages
...is a solid having parallel ends or bases dissimilar in shape with quadrilateral sides. RULK. — To the sum of the areas of the two ends add four times the area of the middle section parallel to them, and TO multiply this sum by one-sixth of the perpendicular height....

## Standard Arithmetic: Embracing a Complete Course for Schools and Academies

William James Milne - 1892 - 440 pages
...frustum, its lower base, and a mean proportional between the two bases. Hence the following rule : RULE. — To the sum of the areas of the two ends add the square root of the product of these areas, and multiply the result by one third of the altitude....

## Longmans' School Mensuration: With an Additional Chapter and Exercises

Alfred John Pearce - 1897 - 202 pages
...— — x volume of FEDC j. jt 1 X 2 X 3 ~ 3 l * .; Volume of frustum = - /S, + V SJ\$T + S2| o I / RULE. — To the sum of the areas of the two ends add the square root of the product of the areas of the two ends, and then multiply the result by one-third...

## Arithmetic for Business with Short Methods and Rapid Calculations in All ...

Jacob Henry Minick, Clement Carrington Gaines - 1904 - 412 pages
...are the lower base, the upper base, and a mean proportional between the bases of the frustum. Hence, RULE. — To the sum of the areas of the two ends add the square root of their product, and multiply this sum by one-third, of the • altitude. EXAMPLES....

## Hodgson's Estimator and Contractor's Guide for Pricing Builder's Work ...

Frederick Thomas Hodgson - 1904 - 364 pages
...length of the base. 90X22X8-i-6=2660 cubic ft. Problem VIII. — To find the solidity of a rectangular prismoid. Rule. — To the sum of the areas of the two ends, abc, def, add four times the area of a section, gh, parallel to and equally distant from the parallel...

## The Curiosity Shop: Or, Questions and Answers Concerning the Lumber Business ...

1906 - 556 pages
...kinds of odd shaped pieces, as will be noted: The usual rule for figuring pieces of this shape is : To the sum of the areas of the two ends add four times the area of the middle section, parallel to them, and multiply this sum by one-sixth of the hight. 1 suggest to...

## The Curiosity Shop: Or, Questions and Answers Concerning the Lumber Business ...

1906 - 566 pages
...kinds of odd shaped pieces, as will be noted: The usual rule for figuring pieces of this shape IB: To the sum of the areas of the two ends add four times the area of the middle section, parallel to them, and multiply this sum by one-sixth of the bight. 1 suggest to...

## The Architect's and Builder's Pocket-book: A Handbook for Architects ...

Frank Eugene Kidder - 1908 - 1784 pages
...— A prismoid is a solid having parallel ends or bases dissimilar in shape with quadrilateral sides. RULE. — To the sum of the areas of the two ends add four times the area of the middle sevtion parallel to them, and"1 multiply this sum by one-sixth of the perpendicular height....