| J. M. Scribner - 1849 - 264 pages
...the Igth. of the base. 90~x 22x8-6=2660 cubic ft. PROBLEM Via To find the Solidity of a Rectangular **Prismoid. Rule. — To the sum of the areas of the two ends,** abc, d ef, add four tunes the area of a section, gh, parallel to and equally distant from the parallel... | |
| Oliver Byrne - 1851 - 310 pages
...inches. And 7140 -r- 1728 = 4-1319 solid feet, the content. To find the solidity of a prismoid. — To **the sum of the areas of the two ends add four times the area of a section parallel to** and equally distant from both ends, and this last sum multiplied by ^ of the height will give the solidity.... | |
| Thomas Tate - 1855 - 286 pages
...ABPE and DCHF, rectangles. A frustum is a cone or pyramid having its top cut off. GENERAL RTJLE. To **the sum of the areas of the two ends, add four times the area of** the middle or mean section parallel to the ends, multiply this sum by the height, and one-sixth the... | |
| Charles Haslett - 1856 - 530 pages
...47 '75 gallons nearly, as before. PROBLEM VI. To find the solid content of the frustum of a pyramid. **RULE. To the sum of the areas of the two ends add** the square root of their product ; multiply this sum by the perpendicular height, and \ of the product... | |
| Anthony Nesbit - 1859 - 494 pages
...of a square pyramid, or a cylindroid ; to find its content in imperial gallons and bushels. KULE. To **the sum of the areas of the two ends, add four times the area of** the middle section parallel to them ; multiply this sum by the perpendicular depth, and \ of the product... | |
| Charles Haslett - 1859 - 572 pages
...47-75 gallons nearly, as before. B PROBLEM VI. To find the solid content of the frustum of a pyramid. **RULE. To the sum of the areas of the two ends add** the square root of their product ; multiply this sum by the perpendicular height, and £ of the product... | |
| Alfred Newsom Niblett - 1861 - 204 pages
...pflrnllelnfrrams. being parallel but not similar to eacli other; and its sides four plane trapezoids. RULES. To **the sum of the areas of the two ends add four times the area of a section parallel to** and equally distant from bo.h ends; multiply this sum by the perpendicular height, and i of the product... | |
| Oliver Byrne - 1863 - 600 pages
...inches. And 7140 -5- 1728 = 4-1319 solid feet, the content. To find the solidity of a prismoid. — To **the sum of the areas of the two ends add four times the area of a section parallel to** and equally distant from both ends, and this last sum multiplied by J of the height will give the solidity.... | |
| Ellwood Morris - 1872 - 206 pages
...means of initial prismoids, which, by a little development, can be made quite useful. Hutton's General **Rule. " To the sum of the areas of the two ends add four times the area of a section parallel to,** and equally distant from, both ends, multiply the last sum by the hight, and J of the product will... | |
| Ellwood Morris - 1872 - 206 pages
...means of initial prismoids, which, by a little development, can be made quite useful. Hutton's General **Rule. " To the sum of the areas of the two ends add four times the area of a section parallel to,** and equally distant from, both ends, multiply the last sum by the bight, and i of the product will... | |
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