| J. M. Scribner - 1844 - 123 pages
...inches 1 Jlns. 32552 cubic ft. PROBLEM VIII. To find the Solidity of a Rectangular Prismoid. AKT. 45. **Rule. — To the sum of the areas of the two ends add four times the area of a section parallel to** and equally distant from the parallel ends, and this sum, multiplied by i of the height, will give... | |
| William WATSON (of Beverley.) - 1845 - 188 pages
...diameters being 20 and 6, and slant height 25. Ans. surf. 1363.4544, sol. 3493.4592. PROBLEM 6. — **To find the solidity of a prismoid. RULE. — To the...add four times the area of a section parallel to,** and equally distant from both ; this sum multiplied by one-sixth of the height, gives the solidity.*... | |
| Scottish school-book assoc - 1845 - 434 pages
...of the edge 15 inches, and the perpendicular height 28 inches? Ans. 3 feet 444 inches. PROBLEM VII. **To find the solidity of a prismoid. RULE. To the sum...add four times the area of a section, parallel to** and equally distant from both ends ; multiply this sum by the perpendicular height, and ^ of the product... | |
| William Kelly (engineer.) - 1847 - 88 pages
...Interval. The usual rule for obtaining the content of a Prismoid as stated by Bonnycastle, is — " To **the sum of the areas of the two ends, add four times the area of a section parallel to** the two ends and equally distant from them, and this sum being multiplied by onesixth of the length,... | |
| 458 pages
...with the result of their project in his behalf." rRODLEM X. To find the solidity of a prismoid. To **the sum of the areas of the two ends add four times the area of a section parallel to** the two ends and equally distant from them ; and this sum being multiplied by one-sixth of the height,... | |
| John Bonnycastle - 1848 - 288 pages
...perpendicular height to be 17.14508 inches? Ans. 3.1006 feet. PROBLEM XI. To find the solidity of a primoid. **RULE.* To the sum of the areas of the two ends add four times the area of a section parallel to** and equally distant from both ends, and this last sum multiplied by i of the height will give the solidity.... | |
| John Bonnycastle - 1848 - 288 pages
...inches? Ans. 3.1006 feet. PROBLEM XL * t To find the solidity of a prismoid. • - . * . • iRULE.* To **the sum of the areas of the two ends add four times the area of a section parallel to** and equally distant from both ends, and this last sum multiplied by | of the height will give the solidity.... | |
| Thomas Tate (mathematical master.) - 1848 - 284 pages
...parallel faces, ABPE and DCHK, rectangles. A frustum is a cone or pyramid having its top cut off. GENERAL **RULE. To the sum of the areas of the two ends, add four times the area of** the middle or mean section parallel to the ends, multiply this sum by the height, and one-sixth the... | |
| Jeremiah Day - 1848 - 153 pages
...what is the solidity? Ans. 5040. PROBLEM VIII. To find the SOLIDITY of a rectangular PRISMOID. 55. To **THE AREAS OF THE TWO ENDS, ADD FOUR TIMES THE AREA OF A** PARALLEL SECTION EQUALLY DISTANT FROM THE ENDS, AND MULTIPLY THE SUM BY -J- OF THE HEIGHT. Let L and... | |
| Almon Ticknor - 1849 - 144 pages
...the solidity ? Ans. 2-9166 cubic feet. \ PROBLEM 20. To find the solidity of a prismoid. EULE. — To **the sum of the areas of the two ends add four times the area of** the section parallel to, and equally distant from both ends, and this last sum multiplied by J of the... | |
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