 | J. M. Scribner - 1844 - 130 pages
...inches 1 Jlns. 32552 cubic ft. PROBLEM VIII. To find the Solidity of a Rectangular Prismoid. AKT. 45. Rule. — To the sum of the areas of the two ends add four times the area of a section parallel to and equally distant from the parallel ends, and this sum, multiplied by i of the height, will give... | |
 | William Watson (of Beverley.) - 1845 - 188 pages
...diameters being 20 and 6, and slant height 25. Ans. surf. 1363.4544, sol. 3493.4592. PROBLEM 6. — To find the solidity of a prismoid. RULE. — To the...add four times the area of a section parallel to, and equally distant from both ; this sum multiplied by one-sixth of the height, gives the solidity.*... | |
 | Scottish school-book assoc - 1845 - 444 pages
...of the edge 15 inches, and the perpendicular height 28 inches? Ans. 3 feet 444 inches. PROBLEM VII. To find the solidity of a prismoid. RULE. To the sum...add four times the area of a section, parallel to and equally distant from both ends ; multiply this sum by the perpendicular height, and ^ of the product... | |
 | William Kelly (engineer.) - 1847 - 88 pages
...Interval. The usual rule for obtaining the content of a Prismoid as stated by Bonnycastle, is — " To the sum of the areas of the two ends, add four times the area of a section parallel to the two ends and equally distant from them, and this sum being multiplied by onesixth of the length,... | |
 | 458 pages
...with the result of their project in his behalf." rRODLEM X. To find the solidity of a prismoid. To the sum of the areas of the two ends add four times the area of a section parallel to the two ends and equally distant from them ; and this sum being multiplied by one-sixth of the height,... | |
 | John Bonnycastle - 1848 - 312 pages
...perpendicular height to be 17.14508 inches? Ans. 3.1006 feet. PROBLEM XI. To find the solidity of a primoid. RULE.* To the sum of the areas of the two ends add four times the area of a section parallel to and equally distant from both ends, and this last sum multiplied by i of the height will give the solidity.... | |
 | John Bonnycastle - 1848 - 320 pages
...inches? Ans. 3.1006 feet. PROBLEM XL * t To find the solidity of a prismoid. • - . * . • iRULE.* To the sum of the areas of the two ends add four times the area of a section parallel to and equally distant from both ends, and this last sum multiplied by | of the height will give the solidity.... | |
 | Thomas Tate (mathematical master.) - 1848 - 284 pages
...parallel faces, ABPE and DCHK, rectangles. A frustum is a cone or pyramid having its top cut off. GENERAL RULE. To the sum of the areas of the two ends, add four times the area of the middle or mean section parallel to the ends, multiply this sum by the height, and one-sixth the... | |
 | Jeremiah Day - 1848 - 354 pages
...what is the solidity? Ans. 5040. PROBLEM VIII. To find the SOLIDITY of a rectangular PRISMOID. 55. To THE AREAS OF THE TWO ENDS, ADD FOUR TIMES THE AREA OF A PARALLEL SECTION EQUALLY DISTANT FROM THE ENDS, AND MULTIPLY THE SUM BY -J- OF THE HEIGHT. Let L and... | |
 | Almon Ticknor - 1849 - 156 pages
...the solidity ? Ans. 2-9166 cubic feet. \ PROBLEM 20. To find the solidity of a prismoid. EULE. — To the sum of the areas of the two ends add four times the area of the section parallel to, and equally distant from both ends, and this last sum multiplied by J of the... | |
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RULE.* To the sum of the areas of the two ends add four times the area of a section parallel to and equally distant from both ends, and this last sum multiplied by £ of the height will give the solidity. 
