 | Lorenzo Fairbanks - 1875 - 468 pages
...what is its entire surface ? PROBLEM II. 730. To find the contents of a frustum of a pyramid, or cone. RULE. — To the sum of the areas of the two ends add the square root of their product, and multiply this sum by one third of the altitude. For the frustum... | |
 | James E. Ryan - 1877 - 212 pages
...area of the base x by the height. 447. XXXI11. THE VOLUME OF PRISMOIDS is COMPUTED BY THE FOLLOWING : RULE. — To the sum of the areas of the two ends add four times the middle section and multiply the sum by one-sixth of the perpendicular height. NOTE. — The length... | |
 | William James Milne - 1877 - 402 pages
...frustum, its lower base, and a mean proportional between the two bases. Hence the following is the RULE. — To the sum of the areas of the two ends add the square root of the product of these areas, and multiply the result by onethird of the altitude.... | |
 | Daniel Kinnear Clark - 1878 - 1022 pages
...which the two ends are dissimilar but parallel plane figures of the same number of sides'). — To the sum of the areas of the two ends, add four times the area of a section parallel to and equally distant from both ends ; and multiply the sum by one-sixth of the length. Nate. — This... | |
 | Clement Mackrow - 1879 - 558 pages
...perpendicular height : the result will be the solidity. 5. To find the solidity of a prisnund. (Pig. 88.) RULE. — To the sum of the areas of the two ends add four times the area of a section parallel to the base and equally distant from both ends ; the sum being multiplied by i the perpendicular height... | |
 | Michael McDermott - 1879 - 540 pages
...greater end, a = area of lesser end, M = area of middle section, and L = length of .section, all in feet. Rule. To the sum of the areas of the two ends, add four times the area of the middle section, multiply this sum by one-sixth of the length, the product will be the required... | |
 | Michael McDermott - 1879 - 560 pages
...area of lesser end, M = area of middle section, and L = length of section, all in feet. l Suit. To the sum of the areas of the two ends, add four times the area of the middle section, multiply this sum by one-sixth of the length, the product will be the required... | |
 | Stephen Roper - 1888 - 702 pages
...which the two ends are dissimilar, but parallel plane figures of the same number of sides). — To the sum of the areas of the two ends, add four times the area of a section parallel to and equally distant from both ends ; and multiply the sum by one-sixth of the length. To find the surface... | |
 | Daniel Kinnear Clark - 1889 - 1030 pages
...solid of which the two ends are unequal but parallel plane figures of the same number of sides). — To the sum of the areas of the two ends, add four times the area of a section parallel to and equally distant from both ends ; and multiply the sum by one-sixth of the length. Note. — This... | |
 | Alexander Wynter Blyth - 1890 - 762 pages
...there are not infrequently rooms in ornamental towers, which may be treated as frustums. The rule is to the sum of the areas of the two ends, add four times the area of the middle or mean section parallel to the ends, multiply this sum by the height, and one-sixth will... | |
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RULE.* To the sum of the areas of the two ends add four times the area of a section parallel to and equally distant from both ends, and this last sum multiplied by £ of the height will give the solidity. 
