| Lorenzo Fairbanks - 1875 - 468 pages
...what is its entire surface ? PROBLEM II. 730. To find the contents of a frustum of a pyramid, or cone. **RULE. — To the sum of the areas of the two ends add** the square root of their product, and multiply this sum by one third of the altitude. For the frustum... | |
| James E. Ryan - 1877 - 212 pages
...area of the base x by the height. 447. XXXI11. THE VOLUME OF PRISMOIDS is COMPUTED BY THE FOLLOWING : **RULE. — To the sum of the areas of the two ends add four times the** middle section and multiply the sum by one-sixth of the perpendicular height. NOTE. — The length... | |
| William James Milne - 1877 - 402 pages
...frustum, its lower base, and a mean proportional between the two bases. Hence the following is the **RULE. — To the sum of the areas of the two ends add** the square root of the product of these areas, and multiply the result by onethird of the altitude.... | |
| Daniel Kinnear Clark - 1878 - 1022 pages
...which the two ends are dissimilar but parallel plane figures of the same number of sides'). — To **the sum of the areas of the two ends, add four times the area of a section parallel to** and equally distant from both ends ; and multiply the sum by one-sixth of the length. Nate. — This... | |
| Clement Mackrow - 1879 - 558 pages
...perpendicular height : the result will be the solidity. 5. To find the solidity of a prisnund. (Pig. 88.) **RULE. — To the sum of the areas of the two ends add four times the area of a section parallel to** the base and equally distant from both ends ; the sum being multiplied by i the perpendicular height... | |
| Michael McDermott - 1879 - 540 pages
...greater end, a = area of lesser end, M = area of middle section, and L = length of .section, all in feet. **Rule. To the sum of the areas of the two ends, add four times the area of** the middle section, multiply this sum by one-sixth of the length, the product will be the required... | |
| Michael McDermott - 1879 - 560 pages
...area of lesser end, M = area of middle section, and L = length of section, all in feet. l Suit. To **the sum of the areas of the two ends, add four times the area of** the middle section, multiply this sum by one-sixth of the length, the product will be the required... | |
| Stephen Roper - 1888 - 702 pages
...which the two ends are dissimilar, but parallel plane figures of the same number of sides). — To **the sum of the areas of the two ends, add four times the area of a section parallel to** and equally distant from both ends ; and multiply the sum by one-sixth of the length. To find the surface... | |
| Daniel Kinnear Clark - 1889 - 1030 pages
...solid of which the two ends are unequal but parallel plane figures of the same number of sides). — To **the sum of the areas of the two ends, add four times the area of a section parallel to** and equally distant from both ends ; and multiply the sum by one-sixth of the length. Note. — This... | |
| Alexander Wynter Blyth - 1890 - 762 pages
...there are not infrequently rooms in ornamental towers, which may be treated as frustums. The rule is to **the sum of the areas of the two ends, add four times the area of** the middle or mean section parallel to the ends, multiply this sum by the height, and one-sixth will... | |
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