 | Jeremiah Day - 1831 - 520 pages
...what is the solidity ? Ans. 5040. PROBLEM VIII. To find the SOLIDITY of a rectangular PRISMOID. 55. To THE AREAS OF THE TWO ENDS, ADD FOUR TIMES THE AREA OF A PARALLEL SECTION EQUALLY DISTANT FROM THE ENDS, AND MULTIPLY THE SUM BY £ OF THE HEIGHT. Let L and... | |
 | Tobias Ostrander - 1833 - 172 pages
...when its ends are right parallelograms. " PROBLEM XVIII, To find the solidity of a prismoid. Rule—To the sum of the areas of the two ends, add four times the area of a section parallel to, and equally distant from, both ends, arid this last sum multiplied by •£ of the height will give... | |
 | William Templeton (engineer.) - 1833 - 224 pages
...gallons nearly as before. •» «bi2&' PROBLEM V. To find the Solid Content of the Frustum of a Pyramid. RULE. — To the sum of the areas of the two ends, add the square root of. their product, multiply this sum by the perpendicular height ; and i of the product... | |
 | Tobias Ostrander - 1834 - 159 pages
...dissimilar. It is a rectangular prismoid when its ends are right parallelograms. ~ ~ " PROBLEM XVIII. To find the solidity of a prismoid. Rule — To the...add four times the area of a section parallel to, and equally distant from, both ends, arid this last sum multiplied by | of the height will give the... | |
 | John Bonnycastle - 1835 - 288 pages
...the solidity, supposing the perpendicular height to be 17.14508 inches? Ans. 3.1006/eef. PROBLEM XI. To find the solidity of a prismoid. RULE.* To the...ends add four times the area of a section parallel to and equally distant from both ends, and this last sum multiplied by £ of the height will give the... | |
 | 1836 - 472 pages
...hight of the wedge and the breadth of the base. To ßnd the solidity of a rectangular prismoid. To the areas of the two ends, add four times the area of a parallel section equally distant from the ends, and multiply the sum by ^ of the hight. A solid is... | |
 | Thomas Holliday - 1838 - 404 pages
...and breadth of each end, and the perpendicular distance between them, for the solidity. Rule.—To the sum of the areas of the two ends, add four times the area of a section parallel to and equally distant from both ends, and this last sum multiplied by one-sixth of the height, will give... | |
 | Jeremiah Day - 1838 - 416 pages
...what is the solidity ? Ans. 5040, PROBLEM VIII. To find the SOLIDITY of a rectangular PRISMOID. 55. To THE AREAS OF THE TWO ENDS, ADD FOUR TIMES THE AREA OF A PARALLEL SECTION EQUALLY DISTANT FROM THE ENDS, AND MULTIPLY THE SUM BY £ OF THE HEIGHT, Let L and... | |
 | Thomas Curtis (of Grove house sch, Islington) - 1839 - 812 pages
...(2 X 64 + 42) X 28 X 9 _, , , , * —~ -— = 7140 solid inches, or 4-1319 solid feet. PROB. XXIX. To find the solidity of a prismoid. Rule. — To the...add four times the area of a section parallel to, and equally distant from, both ends, and multiply the sum by one-tenth of the height for the solidity.... | |
 | Jeremiah Day - 1839 - 432 pages
...what is the solidity ? Ans. 5040. PROBLEM VIII. To find the SOLIDITY of a rectangular PRISMOID. 55. To THE AREAS OF THE TWO ENDS, ADD FOUR TIMES THE AREA OF A PARALLEL SECTION EQUALLY DISTANT FROM THE ENDS, AND MULTIPLY THE SUM BY | OF THE HEIGHT. Let L and... | |
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RULE.* To the sum of the areas of the two ends add four times the area of a section parallel to and equally distant from both ends, and this last sum multiplied by £ of the height will give the solidity. 
