 | John Bonnycastle - 1829 - 256 pages
...and this sum multiplied by the height, and the product again by .5236, will give the solidity. Or, From three times the diameter of the sphere subtract twice the height of the segment, multiply by the square of the height, and that .product by .5236 ; the last product will be the solidity.... | |
 | Edinburgh encyclopaedia - 1830 - 856 pages
...find the solid content of a spherical segment. RULE. From three times the diameter of the sphere, take twice the height of the segment, then multiply the...remainder by the square of the height, and the product by the decimal .5236 for the content. This rule may be derived from Ex. S. Art. l6l. FLUXIONS ; or... | |
 | Thomas Spofford - 1835 - 84 pages
....5236. RULE 2. — From three tim^s the diameter of the Globe, subtract twice the heightof the Segment ; multiply the remainder by the square of the height, and the product by .5236. NOTE. — The surface or nrea of the Frustum is thus found :— as the diameter of the Globe... | |
 | B[enjamin] Franklin Callender - 1836 - 226 pages
...of a Spheroid. From the product of three times the axis, subtract twice the height of the segment ; multiply the remainder -by the square of the height, and the product by .5236. Then, as the square of the axis is to the square of the revolving diameter, so is the last... | |
 | Frederick Augustus Griffiths - 1839 - 348 pages
...find the solid content of a spherical segment. From three times the diameter of the sphere take double the height of the segment; then multiply the remainder by the square of the height, and this product by -5236. Or, To three times the square of the radius of the segment's base add the square... | |
 | J. M. Scribner - 1844 - 130 pages
...and the height of the segment be known, the solidity may be easily found by the following Rule. — From three times the diameter of the sphere, subtract...remainder by the square of the height and the product by the decimal .5236. Ex. 1. What is the solidity of a spherical segment, whose height is 2 feet, cut... | |
 | Benjamin Greenleaf - 1844 - 204 pages
...the contents of a spherical segment. RULE. From three times the diameter of the sphere, take double the height of the segment ; then multiply the remainder by the square of the height, and the product by the decimal .5236 for the contents ; or to three times• the square of the radius of the segment's... | |
 | Benjamin Greenleaf - 1844 - 208 pages
...the contents of a spherical segment. RULE. From three times the diameter of the sphere, take double the height of the segment ; then multiply the remainder by the square of the height, and tJie product by the decimal .5236 for the contents ; or to three times the square of the radius of... | |
 | Benjamin Greenleaf - 1845 - 222 pages
...the contents of a spherical segment. RULE. From three times the diameter of the sphere, take double the height of the segment ; then multiply the remainder by the square of the height, and the product by the decimal .5236 for the contents ; or to three times the square of tlie radius of the segment's... | |
 | Horatio Nelson Robinson - 1845 - 310 pages
...contents of a spherical segment. RULE 9. from three times the. diameter of the sphere, take double the height of the segment ; then multiply the remainder by the square of the height, and that product by the decimal ,5236, and we have the content. The foregoing rules have a variety of practical... | |
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From three times the diameter of the sphere, take double the height of the segment ; then multiply the remainder by the square of the height, and... 
