 | Frank Eugene Kidder - 1892 - 1032 pages
...is a solid having parallel ends or bases dissimilar in shape with quadrilateral sides. RULK. — To the sum of the areas of the two ends add four times the area of the middle section parallel to them, and TO multiply this sum by one-sixth of the perpendicular height.... | |
 | William James Milne - 1892 - 440 pages
...frustum, its lower base, and a mean proportional between the two bases. Hence the following rule : RULE. — To the sum of the areas of the two ends add the square root of the product of these areas, and multiply the result by one third of the altitude.... | |
 | Alfred John Pearce - 1897 - 202 pages
...— — x volume of FEDC j. jt 1 X 2 X 3 ~ 3 l * .; Volume of frustum = - /S, + V SJ$T + S2| o I / RULE. — To the sum of the areas of the two ends add the square root of the product of the areas of the two ends, and then multiply the result by one-third... | |
 | Jacob Henry Minick, Clement Carrington Gaines - 1904 - 412 pages
...are the lower base, the upper base, and a mean proportional between the bases of the frustum. Hence, RULE. — To the sum of the areas of the two ends add the square root of their product, and multiply this sum by one-third, of the • altitude. EXAMPLES.... | |
 | Frederick Thomas Hodgson - 1904 - 370 pages
...length of the base. 90X22X8-i-6=2660 cubic ft. Problem VIII. — To find the solidity of a rectangular prismoid. Rule. — To the sum of the areas of the two ends, abc, def, add four times the area of a section, gh, parallel to and equally distant from the parallel... | |
 | 1906 - 556 pages
...kinds of odd shaped pieces, as will be noted: The usual rule for figuring pieces of this shape is : To the sum of the areas of the two ends add four times the area of the middle section, parallel to them, and multiply this sum by one-sixth of the hight. 1 suggest to... | |
 | 1906 - 566 pages
...kinds of odd shaped pieces, as will be noted: The usual rule for figuring pieces of this shape IB: To the sum of the areas of the two ends add four times the area of the middle section, parallel to them, and multiply this sum by one-sixth of the bight. 1 suggest to... | |
 | Frank Eugene Kidder - 1908 - 1784 pages
...— A prismoid is a solid having parallel ends or bases dissimilar in shape with quadrilateral sides. RULE. — To the sum of the areas of the two ends add four times the area of the middle sevtion parallel to them, and"1 multiply this sum by one-sixth of the perpendicular height.... | |
 | Clement Mackrow - 1916 - 766 pages
...slant height. 3. To find the volume and slant surface of the frustum of a cone or pyramid. (Fig. 74.) RULE. — To the sum of the areas of the two ends add the square root of their product ; this final sum being multU plied by J of the perpendicular height... | |
 | Frederick Thomas Hodgson - 1917 - 696 pages
...length of the base. §0X22X8^6=2660 cubic ft. Problem VIII. — To find the solidity of a rectangular prismoid. Rule. — To the sum of the areas of the two ends, abc , de /, add four times the area of a section, gk, parallel to and equally distant from the parallel... | |
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RULE.* To the sum of the areas of the two ends add four times the area of a section parallel to and equally distant from both ends, and this last sum multiplied by £ of the height will give the solidity. 
