 | William Guy Peck - 1876 - 376 pages
...equal in all their parts, (P. 11). Hence, the angle A is equal to C, which was to be proved. Cor. 2. A line drawn from the vertex of an isosceles triangle to the middle of the base bisects the angle at the vertex, and is perpendicular to the base. For, from what has just been proved,... | |
 | William Guy Peck - 1876 - 412 pages
...all their parts, ( P. 11 ). Hence, the angle A is equal to C, which was to be proved. BOOX 1. Cor. 2. A line drawn from the vertex of an isosceles triangle to the middle of the bose bisects the angle at the vertex, and is perpendicular to the base. For, from what has just been... | |
 | Moffatt and Paige - 1879 - 474 pages
...than two right angles. (21)- Draw a triangle which shall be equal to two other given triangles. (22) A line drawn from the vertex of an isosceles triangle to the middle point of the base is at right angles to it. (23) A line making equal angles with the sides of an isosceles... | |
 | George Anthony Hill - 1880 - 348 pages
...conclusionsare: CDbisects AB,a.nd CD bisects AC B. Prove by showing that AA CD I!. The line joining the vertex of an isosceles triangle to the middle of the base is perpendicular to the base, and bisects the angle at the vertex. Hints. — In -this case what are the hypotheses? the conclusions?... | |
 | Elias Loomis - 1880 - 456 pages
...the last two angles is a right angle. Hence the arc drawn from the vertex of an isosceles spherical triangle to the middle of the base is perpendicular to the base, and also bisects the vertical angle. PROPOSITION XVI. THEOREM. In a spherical triangle, the greater... | |
 | Charles Davies, Adrien Marie Legendre - 1885 - 538 pages
...is equal to DAC, and BDA to CDA : hence, the last two are right angles. Consequently, a straight Hne drawn from the vertex of an isosceles triangle to the middle of the base, bisects the angle at the vertex, and is perpendicular to the base. PROPOSITION XII. THEOREM. // two... | |
 | William Chauvenet - 1887 - 336 pages
...to the included angle EGF. Hence the triangles are equal, by Proposition VI. EXERCISE. Theorem.— A line drawn from the vertex of an isosceles triangle to the middle point of the base is perpendicular to the base, and bisects the vertical angle. PROPOSITION X.— THEOREM.... | |
 | Edward Albert Bowser - 1890 - 420 pages
...equiangular. (706) 713. COR. 2. The arc of a great circle drawn from the vertex of an isosceles spherical triangle to the middle of the base is perpendicular to the base, and bisects the vertical angle. POLAR TRIANGLES. V14. One spherical triangle is called the polar triangle... | |
 | Rupert Deakin - 1891 - 102 pages
...usually stated. For example, almost all editions of Euclid contain this Eider : — " The straight line drawn from the vertex of an isosceles triangle to the middle point of the base is perpendicular to the base." Boys who have learnt Euclid for years will refuse... | |
 | Arthur Latham Baker - 1893 - 154 pages
...equiangular, and the Sph. /_ at the base are equal, Q. E E. 273. COR. 9. The arc of a great circle drawn from the vertex of an isosceles triangle to the middle of the base, bisects the rertical angle, is perpendicular to the base, and divides the triangle into two symmetrical... | |
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Consequently, a line drawn from the vertex of an isosceles triangle to the middle of the base, bisects the vertical angle, and is perpendicular to the base. 
