 | Henry William Jeans - 1870 - 288 pages
...get the true altitude. Subtract the true altitude from 90° to get the true zenith distance. 4. Mark the zenith distance north or south according as the zenith is north or south of the planet. 132 EXAMPLE. 338. November 20, 1853, at 6h 18m л.M., mean time nearly, in long. 62' 42' E.,... | |
 | Lowis D'Aguilar Jackson - 1880 - 524 pages
...the corrected altitude from 90°, and thus obtain the true zenith distance, which is then marked as north or south, according as the zenith is north or south of the celestial body ; then, if the declination is similarly marked in the Nautical Almanac, the sum of the... | |
 | Lowis d'Aguilar Jackson - 1880 - 520 pages
...the corrected altitude from 90°, and thus obtain the true zenith distance, which is then marked as north or south, according as the zenith is north or south of the celestial body ; then, if the declination is similarly marked in the Nautical Almanac, the sum of the... | |
 | Nathaniel Bowditch - 1906 - 670 pages
...its zenith distance. From the figure we have: jrIQ 42. By attending to the names of z and d, marking the zenith distance north or south according as the zenith is north or south of the body, the above equation may be considered general for any position of the body at upper transit, as... | |
 | Nathaniel Bowditch - 1925 - 868 pages
...distance. From the figure we have: )M + MZ, or M FIG. 63. By attending to the names of z and d, marking the zenith distance north or south according as the zenith is north or south of the body, the above equation may be considered general for any position of the body at upper transit, as... | |
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