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" To find the Area of a Triangle when the Three Sides are given. Rule. — From half the sum of the three sides subtract each side separately. "
A Treatise on Surveying, Containing the Theory and Practice: To which is ... - Page 97
by John Gummere - 1814 - 346 pages
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Elementary Geometry: With Applications in Mensuration

Charles Davies - 1850 - 218 pages
...a triangle whose base is 72,7 yards, and altitude 36,5 yards ? Ans. 1326,775 sq. yds. PROBLEM III. To find the area of a triangle when the three sides are known. RULE, I. Add" the three sides together and take half their sum. II. From this half sum take...
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The Practical Model Calculator: For the Engineer, Mechanic, Machinist ...

Oliver Byrne - 1851 - 310 pages
...A " " 7 J pa. = area required. To find the area of a triangle whose three sides only are given. — From half the sum of the three sides subtract each...severally. Multiply the half sum and the three remainders continually together, and the square root of the product will be the area required Required the area...
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An elementary course of practical mathematics, Part 2

James Elliot - 1851 - 152 pages
...side of the base being 35 feet; and the perpendicular height 42 feet?* Ans. 4410 sq. ft. PROBLEM V. To find the Area of a Triangle when the Three Sides are given. RULE. Add together the three sides, and halve the sum. From the half sum subtract each side separately. Multiply...
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Arithmetic, Practically Applied ...

Horace Mann - 1851 - 384 pages
...frustum, &c.) ; ub the upper base. 1. THE PARALLELOGRAM. a = bx al. 2. THE TRIANGLE. a = — -?-. H To find the area of a triangle, when the three sides are given : I. Add the three sides together, and take half their sum. II. From this half sum take each side separately....
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A Theoretical and Practical Arithmetic: Designed for Common Schools and ...

Daniel Leach - 1851 - 280 pages
...is 80 yards ? 364. To find the area of a triangle, when the length of its three sides is known,— RULE. From half the sum of the three sides subtract each side separately. Then multiply the half sum by each side in succession. The square root of the continued...
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Mathematical Recreations: Containing Solutions of Many Very Difficult and ...

Horatio Nelson Robinson - 1851 - 96 pages
...TRIGONOMETRICAL THEOREMS AND PROBLEMS. In all works on Surveying, we find the following rule for determining the area of a triangle when the three sides are given. RULE. Find the half sum of the three sides, and from said half sum take each side severally, thus obtaining...
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A Theoretical and Practical Arithmetic: Designed for Common Schools and ...

Daniel Leach - 1853 - 622 pages
...a triangle ? 364. To find the area of a^ triangle, when the length of its three sides is known, — RULE. From half the sum of the three sides subtract each side separately. Then multiply the half sum by each side in succession. The square root of the continued...
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The operative mechanic's workshop companion, and the scientific gentleman's ...

William Templeton (engineer.) - 1855 - 326 pages
...feet, the area. 2 When only the three sides of a triangle can t>e given, to find the area. Mule. — From half the sum of the three sides, subtract each...severally; multiply the half sum and the three remainders together, and the square root of the product is equal to the area required. Required the area of a...
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Elements of Plane and Spherical Trigonometry: With Their Applications to ...

Elias Loomis - 1855 - 192 pages
...feet, and the included angle 67° 15' ? Ans. (85.) When the three sides are known, we may use RULE III. From half the sum of the three sides subtract each side severally ; multiply together the half sum and the three remainders, and extract the square root of the product. Demonstration....
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Elements of Plane Trigonometry, Surveying and Navigation

William Smyth - 1855 - 234 pages
...16f(s— c) (s— i) (s — a). Dividing next both sides by 16 and extracting the square root, Hence, to find the area of a triangle when the three sides are given ; Subtract successively each side from the half sum of the sides ; multiply together the half sum and...
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