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" To find the Area of a Triangle. Rule ] . Multiply the base by the perpendicular height, and half the product will be the area. "
An Introduction to Mensuration and Practical Geometry - Page 54
by John Bonnycastle - 1833 - 288 pages
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The Computist's Manual of Facts: And Merchant's and Mechanic's Calculator ...

Ezra S. Winslow - 1853 - 264 pages
...distance from the side FG to the side HI being 8 feet? 12 X 8 = 96 square feet. Ans. OF TRIANGLES. To find the area of a triangle. RULE. — Multiply the base by half the perpendicular height, or the perpendicular height by half the base, and the product is the...
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Cyclopedia of Architecture: Historical, Descriptive, Typographical ...

Robert Stuart - 1854 - 1272 pages
...б chains, and perpendicular height 5. > Answer 30 Prob. 2. To find the area of a triangle. Rule 1. Multiply the base by the perpendicular height, and half the product will be the area. Rule 2. When the three sides only are given : add the three sides together, and take half the sum;...
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Principles of geometry, mensuration, trigonometry, land-surveying and levelling

Thomas Tate - 1855 - 296 pages
...2. PROBLEM. To find the area of a triangle when its base . and perpendicular height are given. BULK. Multiply the base by the perpendicular height, and half the product will be the area. See Geo. p. 35. EXAMPLES. 1. Required the number of acres in the triangular field ABC, whose base AB...
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Practical Arithmetic, by Induction and Analysis

Joseph Ray - 1857 - 348 pages
...what cost a roof 40ft. long, the rafters on each side 18 ft 6 in. long ? Ans. $51.80 / » ART. 313. To FIND THE AREA OF A TRIANGLE. Rule. — Multiply the base by the perpendicular hight. and take half the product for the area. Or, when the sides are given, the following RULE : 1st....
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A Treatise on Arithmetic, Combining Analysis and Synthesis: Adapted to the ...

James Stewart Eaton - 1857 - 376 pages
...adjacent angle at that base, assuming the longer sides for bases ? Ans. 2436 sq. rd. 466. PROB. 2. — To find the area of a triangle. RULE. — Multiply the base by half the altitude, or half the base by the altitude. Ex. 1. What is the area of a triangle whose base...
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Text-book of Modern Carpentry: Comprising a Treatise on Building-timber ...

Thomas William Silloway - 1858 - 236 pages
...and the product will be the area. PROBLEM II. TO FIND THE AREA OF A TRIANGLE. RULE. — Multiply tlie base by the perpendicular height, and half the product will be the area. PROBLEM III. TO FIND THE AREA OF A TRIANGLE WHOSE THREE SIDES ABE GIVEN. RULE. — From the half-sum...
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A treatise on problems of maxima and minima, solved by algebra. Repr. under ...

Rāmachandra (son of Sundara Lāla.) - 1859 - 250 pages
....-. - Z. - = i equation to the Sphere. (5.) TO FIND THE AREA OF A TKIANGLE. (Fig. 4.) Rule 1st. — Multiply the base by the perpendicular height, and half the product will be the area. The truth of this rule is evident, because any triangle is the half a parallelogram of equal base and...
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The Artillerists̓ Manual, and British Soldiers̓ Compendium

Frederick Augustus Griffiths - 1859 - 426 pages
....1 .r 4 .'> (1 7V EB To find the area of a triangle, its base, and perpendicular height being given. Multiply the base by the perpendicular height, and half the product will be the area. Example. — Required the number of square yards contained in a triangle, whose base is 20 yards, and...
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A handbook of practical gauging

Janes Boddely Keene - 1861 - 104 pages
...side is 3 yards, and height 3ft. 6in. » Ans. 31ft. 6 parts. Tofind the Area of a Triangle. BCLE. — Multiply the base by the perpendicular height, and half the product will be the area. NOTE. — By adding a similar and equal triangle to the one to be measured, a parallelogram is obtained,...
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The young gardener's educator

William Keane (gardener.) - 1861 - 252 pages
...content of a triangular field whosebase is 6 chains 50 links, and perpendicular height 5 chains 60 links. Rule : — Multiply the base by the perpendicular height and half the product will be the area ; or multiply the one of these divisions by half the other. 6-50 6,50 5-80 2-80 G 39000 32500 \ 52000...
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