 | John Radford Young - 1850 - 294 pages
...are sides of the two ends of the frustum ; the area of each trapezoidal face is found by multiplying the sum of the parallel sides by the perpendicular distance between them — that is, by the slant height of the frustum — and diriding by 2 ; and as the faces are all equal,... | |
 | Daniel Adams - 1850 - 144 pages
...number of square inches in the trapezoid. Hence, To find the area of a trapezoid. Multiply one half the sum of the parallel sides by the perpendicular distance between them. EXAMPLES FOR PRACTICE. 1. What are the square contents of a board 12 feet long, 16 inches wide at one... | |
 | Oliver Byrne - 1851 - 310 pages
...required. To find the area of a trapezoid, or a quadrangle, two of ivJwse opposite sides are parallel. — Multiply the sum of the parallel sides by the perpendicular...between them, and half the product will be the area. Required the area of the trapezoid ABCD, whose sides AB and DC are 321-51 and 214-24, and perpendicular... | |
 | Oliver Byrne - 1852 - 600 pages
...requiredTo find the area of a trapezoid, or a quadrangle, two of whose opposite sides are parallel- — Multiply the sum of the parallel sides by, the perpendicular...distance between them, and half the product will be the areaRequired the area of the trapezoid ABCD, whose sides AB and DC are 321-51 and 214-24, and perpendicular... | |
 | Septimus Norris - 1852 - 356 pages
...the Area of a Trapezoid, fig- 9RULE 1- — Multiply the sum of the two parallel sides, ab, dc, by ap, the perpendicular distance between them, and half the product will be the areaRULE 2- — Draw a diagonal, ac, to divide the trapezoid into two triangles ; find the areas of... | |
 | Thomas Kentish - 1852 - 272 pages
...equal to the product of the length and breadth. The area of a trapezoid is found by multiplying half the sum of the parallel sides by the perpendicular distance between them. A triangle is half a rectangle, and therefore its area is half the product of the height and base.*... | |
 | Robert Stuart - 1854 - 1272 pages
...189 AB has been subtracted. 189 Prob. 4. To find the area of a trapezoid. Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area. Ex. In a trapezoid, the parallel sides are AB 7, and CD 12, and the perpendicular distance AP or CN... | |
 | Andrew Duncan (Surveyor) - 1854 - 156 pages
...the farm, which is plain from the figure. 15th. To find the area of a Trapezoid Rule, multiply half the sum of the parallel sides by the perpendicular distance between them, and the product is the area. Let figure 12 be a Trapazoid ; if AD be a \-r bisected in E, and E " F drawn... | |
 | Thomas Kentish - 1854 - 268 pages
...equal to the product of the length and breadth. The area of a trapezoid is found by multiplying half the sum of the parallel sides by the perpendicular distance between them. A triangle is half a rectangle, and therefore its area is half the product of the height and base.*... | |
 | Charles Davies - 1855 - 340 pages
...ground : required the breadth of the streetArts 77-8875 ftPROBLEM VITo find the area of a trapezoidB-ULE Multiply the sum of the parallel sides by the perpendicular distance between them, and then divide the product by two : the quotient mil be the area (Bk- IV- Th- x)EXAMPLES D 1 - Required... | |
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RULE.* Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area. 
