 | Robert Stuart - 1854 - 1272 pages
...189 AB has been subtracted. 189 Prob. 4. To find the area of a trapezoid. Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area. Ex. In a trapezoid, the parallel sides are AB 7, and CD 12, and the perpendicular distance AP or CN... | |
 | Andrew Duncan (Surveyor) - 1854 - 156 pages
...the farm, which is plain from the figure. 15th. To find the area of a Trapezoid Rule, multiply half the sum of the parallel sides by the perpendicular distance between them, and the product is the area. Let figure 12 be a Trapazoid ; if AD be a \-r bisected in E, and E " F drawn... | |
 | Thomas Kentish - 1854 - 268 pages
...equal to the product of the length and breadth. The area of a trapezoid is found by multiplying half the sum of the parallel sides by the perpendicular distance between them. A triangle is half a rectangle, and therefore its area is half the product of the height and base.*... | |
 | Charles Davies - 1855 - 340 pages
...ground : required the breadth of the streetArts 77-8875 ftPROBLEM VITo find the area of a trapezoidB-ULE Multiply the sum of the parallel sides by the perpendicular distance between them, and then divide the product by two : the quotient mil be the area (Bk- IV- Th- x)EXAMPLES D 1 - Required... | |
 | William Mitchell Gillespie - 1855 - 436 pages
...figures, two opposite sides of which are parallel. The content of a Trapezoid equals half the product of the sum of the parallel sides by the perpendicular distance between them. If the given quantities are the four sides a, 6, <?, c?, of which b and d are parallel ; then, making... | |
 | William Mitchell Gillespie - 1856 - 478 pages
...figures, two opposite sides of which are parallel. The content of a Trapezoid equals half the product of the sum of the parallel sides by the perpendicular distance between them. If the given quantities are the four sides a, b, c, d, of which b and d are parallel ; then, making... | |
 | William Mitchell Gillespie - 1857 - 538 pages
...two opposite sides of •which are parallel. The content of a Trapezoid equals half the product of the sum of the parallel sides by the perpendicular distance between them. If the given quantities are the four sides a, b, e, d, of which b and d are parallel ; then, making... | |
 | Horatio Nelson Robinson - 1859 - 348 pages
...length of a trapezoid is one / half the sum of the parallel sides ; hence the Zi RULE. Multiply one half the sum of the parallel sides by the perpendicular distance between them. EXAMPLES FOR PRACTICE. 1. What are the square contents of a board 12 feet long, 16 inches wide at one... | |
 | William Easton (of Hereford.) - 1859 - 110 pages
...the sides are 2000, 3600, 2800, 4200, and diagonal 48OO links, at 25s. an acre. Rule. Multiply half the sum of the parallel sides by the perpendicular distance between them. Find the area of the following trapezoids. 33. Parallel sides 53 and 67 ft., perpendicular distance... | |
 | Horatio Nelson Robinson - 1860 - 444 pages
...length of a trapezoid is one / half the sum of the parallel sides ; hence the [\ RULE. Multiply one naif the sum of the parallel sides by the perpendicular distance between them. EXAMPLES FOR PRACTICE. 1. What are the square contents of a board 12 feet long, 16 inches wide at one... | |
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RULE.* Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area. 
