 | William Grier - 1842 - 320 pages
...160, then, v/(160 X 40) : 60 :: 200 : 150 = the conjugate axis. 4. To find the transverse axis. Take the square root of the difference of the squares of the ordinate and half conjugate, and add to this the half conjugate if the lesser absciss is used, but subtract the... | |
 | John Bonnycastle - 1843 - 122 pages
...25 : : 14 : 10=the ordinale required. CASE II. — PAGE 95. Ex. 2. Here Via.52— 102= 756.25=7.5 = the square root of the difference of the squares of the ordinate and semi-conjugate, And 25 : 35 : : 7.5 : 10.5 = the distance between the ordinate and centre, Hence semi-transverse 17.5... | |
 | Charles Haynes Haswell - 1844 - 298 pages
...of half the conjugate add the square of the ordinate, and extract the square root of that sum. Then, as the conjugate diameter is to the transverse, so is the square root to half the sum of the abscissae. To this half sum add half the transverse diameter for the greater... | |
 | Nathan Scholfield - 1845 - 542 pages
...When the major, and minor axes, and ordinate are given. RULE. As the axis-minor is to the axis-major, so is the square root of the difference of the squares of the semi-minor axis and ordinate, to the distance between the ordinate and centre ; which distance, added... | |
 | Nathan Scholfield - 1845 - 894 pages
...When the major, and minor axes, and ordinate are given. RULE. As the axis-minor is to the axis-major, so is the square root of the difference of the squares of the semi-minor axis and ordinate, to the distance between the ordinate and centre ; which distance, added... | |
 | Nathan Scholfield - 1845 - 506 pages
...the major, and minor axes, and ordinate are given. RULE. As the axis-minor is to the axis-major,so is the square root of the difference of the squares of the semi-minor axis and ordinate, to the distance between the ordinate and centre ; which distance, added... | |
 | John Bonnycastle - 1848 - 312 pages
...x X (t — a-) : if ; and from this the four rules here given are deduced, c •Jft CONIC SECTIONS. RULE.* As the conjugate diameter is to the transverse,...semi-transverse, will give the two abscissas required. EXAMl'LES. 1. The transverse diameter AB is 120, the conjugate diameter CD is 40, and the ordinate... | |
 | Charles Haynes Haswell - 1851 - 346 pages
...of half the conjugate add the square of the ordinate, and extract the square root of that sum. Then, as the conjugate diameter is to the transverse, so is the square root to half the sum of the abscissae. To this half sum add half the transverse diameter for the greater... | |
 | Septimus Norris - 1852 - 356 pages
...of half the conjugate add the square of the ordinate, and extract the square root of that sumThen, as the conjugate diameter is to the transverse, so is the square root to half the sum of the abscissaeTo this half sum add half the transverse diameter for the greater abscissa,... | |
 | Charles Haynes Haswell - 1853 - 318 pages
...The Transverse and Conjugate diameters, and an Ordinate being known, to find the Abscissa — fig. 3. RULE. — As the conjugate diameter is to the transverse,...ordinate and semiconjugate to the distance between the ordkiate and centre ; and this distance, being added to and subtracted from the semi-transverse, will... | |
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As the conjugate diameter is to the transverse, So is the square root of the difference of the squares of the ordinate and semi-conjugate, To the distance between the ordinate and centre. 
