 | Leonard Elliott Brookes - 1906 - 664 pages
...perpendicular height. Parallelogram : A rea = D XH To find the area of a trapezoid— Fig. 45. Multiply half the sum of the two parallel sides by the perpendicular distance between the sides. (HE+D) 2 Trapezoid: Area= U — D •! Fig. 48. To find the area of an equilateral triangle—... | |
 | Joseph H. Rose - 1906 - 340 pages
...perpendicular height. Parallelogram : Area = DXH To find the area of a trapezoid— Fig. 59. Multiply half the sum of the two parallel sides by the perpendicular distance between the sides. _ . , . (HE + D) TrapezoId : Area = ^ To find the area of an equilateral triangle — Fig.... | |
 | Charles Westinghouse - 1906 - 168 pages
...perpendicular height. Parallelogram : Area=D x H To find the area of a trapezoid— Fig. 92. Multiply half the sum of the two parallel sides by the perpendicular distance between the sides. Polygon: Area= No. of si Trapezoid: Area= (HE+D) To find the area of an equilateral triangle... | |
 | Alice Ravenhill - 1907 - 762 pages
...the area of a triangle. Base x perpendicular height, divide by 2. To find the area of a trapezoid. Multiply the sum of the two parallel sides by the perpendicular distance between them, divide by 2. To find the area of any rectilinear figure. Divide the figure into triangles by lines... | |
 | Frank Eugene Kidder - 1908 - 1784 pages
...angles, and divide the product by 2. Or, area (Fig. 27). To find the area of a Irapezoid (Fig. 28). RULE. — Multiply the sum of the two parallel sides by the perpendicular distance between them, and divide the product by 2. To compute Ihe area of an irregular polygon. RI-LE. — Divide the polygon... | |
 | DeForest A. Preston, Edward Lawrence Stevens - 1910 - 380 pages
...diameter x .7854. HaBe Width Base 146. The area of a trapezoid is found by multiplying the average length of the two parallel sides by the perpendicular distance between them, and expressing the result in square units. The average length of the two sides is ^ of their sum. 147.... | |
 | Thomas Aloysius O'Donahue - 1911 - 288 pages
...S = |(AB + BC + CA). (12) (Fig. 63) Area = VS(S - AB)(S - BC)(S - OA). Trapezoid. — Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area. B (13) (Fig. 64) Area = |(AD + BC) x DE. FIG. ' B Fio. 64. If the lengths... | |
 | Frank Eugene Kidder - 1915 - 1856 pages
...and divide the product by 2. Thus, ab X (ce + di) To find the area of a trapezoid (Fig. 28). Rnle. Multiply the sum of the two parallel sides by the perpendicular distance between them and divide the product by 2. To compute the area of an irregular polygon. Rnle. Divide the polygon into... | |
 | Frederick Thomas Hodgson - 1917 - 696 pages
...diagonal, ac, is 42 feet, and the two perpendiculars, de and bf, 18 and l(i feet? Problem IV. — To find the area of a trapezoid. Rule. — Multiply the sum...between them, and half the product will be the area. Example i. — Required the area of the trapezoid, abed, having given ab = 321.51 d feet, dc= 214.24... | |
 | William Miller Barr - 1918 - 650 pages
...Trapezoid, or a Quadrangle, Two of Whose Opposite Sides Are Parallel. — Rule: Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area. To Find the Area of a Regular Polygon. — Rule: Multiply half the perimeter of the figure by the perpendicular... | |
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Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area. 
