 | International Correspondence Schools - 1901 - 570 pages
...63. When the three sides of • • a triangle are given, its area is found by the following rule: Rule. — From half the sum of the three sides, subtract each side separately; find the continued product of the half sum of the sides and thc three remainders; the square... | |
 | James Sherman Hunter - 1902 - 426 pages
...problems are all very brief by canceling. To find the area of any triangle when the three sidtt only are given. RULE. — From half the sum of the three sides subtract each side severally; multiply these three remainders and the said half sum continually together ; then the square root of the last... | |
 | William Kent - 1907 - 1206 pages
...altitude. RULE 2. Multiply half the product of two sides by the sine of the Included angle. RULES. From half the sum of the three sides subtract each side severally; multiply together the half sum and the three remainders, and extract the square root of the product. The area... | |
 | Joseph H. Rose - 1906 - 340 pages
...C Sum of sides To find the area of any oblique angled triangle when only the three sides are given. From half the sum of the three sides, subtract each...severally. Multiply the half sum and the three remainders together and the square root of the product is equal to the area required. Area=i/S(S— A) (8— B)... | |
 | Charles Westinghouse - 1906 - 168 pages
...(SC) Sum of sides To find the area of any oblique angled triangle when only the three sides are given. From half the sum of the three sides, subtract each...severally. Multiply the half sum and the three remainders together and the square root of the products is equal to the area required. Area=i/S(S— A) (8—... | |
 | International Correspondence Schools - 1906 - 620 pages
...vertex. 47. To find the area of a triangle from the lengths of its three sides, apply the following: Rule. — From half the sum of the three sides subtract each side separately; multiply together the half sum and the three remainders and extract the square root of... | |
 | Calvin Franklin Swingle, Frederick John Prior - 1906 - 676 pages
...height of any oblique angled triangle— Fig. 61. From half the sum of the three sides of the triangle, subtract each side severally. Multiply the half sum and the three remainders together and twice the square root of the result divided by the base of the triangle be the height... | |
 | Gustavus Sylvester Kimball - 1911 - 444 pages
...feet. Solution. (20+30+40) -5-2 =45; 45-20 = 25; 45-30 = 15; 45-40 = 5. ^45X25X15X5 = 290.4 + ft. 357. Rule. From half the sum of the three sides, subtract each side separately. Multiply the half sum and the three remainders together, and extract the square root of... | |
 | Henry Adams - 1913 - 300 pages
...three sides only of a triangle is given, the calculation is a little more complicated. The rule is : From half the sum of the three sides subtract each side severally, and multiply it and the three remainders together and take the square root for the area. This is usually... | |
 | William Miller Barr - 1918 - 650 pages
...area divided by the base. To Find the Area of a Triangle Whose Three Sides Only Are Given. — Rule 1. From half the sum of the three sides subtract each side severally. Multiply half the sum and the three remainders continually together, and the square root of the product will... | |
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... and 48° 15'? Ans. 6 A. 3 R. 18 P. PROBLEM V. To find the area of a triangle when the three sides are given. RULE. From half the sum of the three sides... 
