| International Correspondence Schools - 1901 - 570 pages
...63. When the three sides of • • a triangle are given, its area is found by the following rule: **Rule. — From half the sum of the three sides, subtract each side** separately; find the continued product of the half sum of the sides and thc three remainders; the square... | |
| James Sherman Hunter - 1902 - 426 pages
...problems are all very brief by canceling. To find the area of any triangle when the three sidtt only **are given. RULE. — From half the sum of the three sides subtract each side severally; multiply** these three remainders and the said half sum continually together ; then the square root of the last... | |
| William Kent - 1907 - 1206 pages
...altitude. RULE 2. Multiply half the product of two sides by the sine of the Included angle. RULES. **From half the sum of the three sides subtract each side severally; multiply** together the half sum and the three remainders, and extract the square root of the product. The area... | |
| Joseph H. Rose - 1906 - 340 pages
...C Sum of sides To find the area of any oblique angled triangle when only the three sides are given. **From half the sum of the three sides, subtract each...severally. Multiply the half sum and the three remainders** together and the square root of the product is equal to the area required. Area=i/S(S— A) (8— B)... | |
| Charles Westinghouse - 1906 - 168 pages
...(SC) Sum of sides To find the area of any oblique angled triangle when only the three sides are given. **From half the sum of the three sides, subtract each...severally. Multiply the half sum and the three remainders** together and the square root of the products is equal to the area required. Area=i/S(S— A) (8—... | |
| International Correspondence Schools - 1906 - 620 pages
...vertex. 47. To find the area of a triangle from the lengths of its three sides, apply the following: **Rule. — From half the sum of the three sides subtract each side** separately; multiply together the half sum and the three remainders and extract the square root of... | |
| Calvin Franklin Swingle, Frederick John Prior - 1906 - 676 pages
...height of any oblique angled triangle— Fig. 61. From half the sum of the three sides of the triangle, **subtract each side severally. Multiply the half sum and the three remainders** together and twice the square root of the result divided by the base of the triangle be the height... | |
| Gustavus Sylvester Kimball - 1911 - 444 pages
...feet. Solution. (20+30+40) -5-2 =45; 45-20 = 25; 45-30 = 15; 45-40 = 5. ^45X25X15X5 = 290.4 + ft. 357. **Rule. From half the sum of the three sides, subtract each side** separately. Multiply the half sum and the three remainders together, and extract the square root of... | |
| Henry Adams - 1913 - 300 pages
...three sides only of a triangle is given, the calculation is a little more complicated. The rule is : **From half the sum of the three sides subtract each side severally,** and multiply it and the three remainders together and take the square root for the area. This is usually... | |
| William Miller Barr - 1918 - 650 pages
...area divided by the base. To Find the Area of a Triangle Whose Three Sides Only Are Given. — Rule 1. **From half the sum of the three sides subtract each side severally. Multiply** half the sum and the three remainders continually together, and the square root of the product will... | |
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