 | Christian Brothers - 1888 - 482 pages
...— 25 = 2? 52 — 39 = 13 52 — 40 = 12 52 x 27 x 13 x 12 = 219024 Area = -v/219024 = 468 sq. yd. RULE. — From half the sum of the three sides, subtract each side separately ; then multiply the half sum and the three remainders together; and the square root of the... | |
 | James William Nicholson - 1889 - 408 pages
...15. 15 — 5 = 10, 15 — 12 = 3, 15 — 13 = 2. 15 X 10 X 3 X 2 = 900; v'itOO = 30, Ans. in sq. in. RULE. — From half the sum of the three sides subtract each side; then multiply the half sum and the three remainders together , and extract the square root of the product.... | |
 | John Groesbeck - 1891 - 426 pages
...tapers to a point. Find the value at 4^ cents per square foot. Ans. 63 cents. 447. To find the Area of a Triangle when the Three Sides are given. Rule. —...half the sum of the three sides subtract each side separately. Multiply the half sum and the three remainders together, and extract the square root of... | |
 | Thomas Baker - 1891 - 264 pages
...has been made, and the work must be repeated. TO FIND THE AREA OF A TRIANGLE FROM THE THREE SIDES. RULE. From half the sum of the three sides subtract each side severally and reserve the three remainders ; multiply the half sum continually by the three remainders, and the... | |
 | Horatio Nelson Robinson - 1892 - 430 pages
...50) -=- 2 = 60 ; 60 - 30 = 30 ; 60 - 40 = 20; 60 - 50 = 10. \X60~x30 x 20 x 10 = 600 sq. ft., area. RULE. — From half the sum of the three sides subtract each side separately; multiply the half-sum and the three remainders together; the square root of the product... | |
 | Horatio Nelson Robinson - 1892 - 428 pages
...+ 50) -4- 2 = 60 ; 60 - 30 = 30 ; 60 - 40 = 20 ; 60 - 50 = 10. V60x30x20xlo' = 600 sq. ft. , area. RULE. — From half the sum of the three sides subtract each side separately ; multiply the half-sum and the three remainders together; the square root of the product... | |
 | Massachusetts - 1893 - 986 pages
...given. Rule. — Take one-half the product of the side and perpendicular, and divide by 160. (ft) When three sides are given. Rule. — From half the sum of the three sides subtract each side separately ; multiply the half sum and the three remainders together; the square root of the product... | |
 | William Kent - 1895 - 1244 pages
...altitude. RULE a. Multiply half the product of two sides by the sine of the Included angle. Ri'LE 3. From half the sum of the three sides subtract each side severally; multiply together the half sum and the three remainders, and extract the square root of the product. The area... | |
 | Peder Lobben - 1899 - 460 pages
...circle of the same area. To Figure the Area of Any TriangIe when Only the Length of the Three Sides is Given. RULE. From half the sum of the three sides subtract each side separately ; multiply these three remainders with each other and the product by half the sum of the... | |
 | William Whitehead Rupert - 1900 - 148 pages
...God, for which reason He always is God." CHAPTER V. THE AREA OF A TRIANGLE IN TERMS OF ITS SIDES. 48. RULE. — From half the sum of the three sides subtract each side separately ; multiply together the half sum and the three remainders and extract the square root of... | |
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... and 48° 15'? Ans. 6 A. 3 R. 18 P. PROBLEM V. To find the area of a triangle when the three sides are given. RULE. From half the sum of the three sides... 
