| Christian Brothers - 1888 - 482 pages
...— 25 = 2? 52 — 39 = 13 52 — 40 = 12 52 x 27 x 13 x 12 = 219024 Area = -v/219024 = 468 sq. yd. **RULE. — From half the sum of the three sides, subtract each side** separately ; then multiply the half sum and the three remainders together; and the square root of the... | |
| James William Nicholson - 1889 - 408 pages
...15. 15 — 5 = 10, 15 — 12 = 3, 15 — 13 = 2. 15 X 10 X 3 X 2 = 900; v'itOO = 30, Ans. in sq. in. **RULE. — From half the sum of the three sides subtract each side;** then multiply the half sum and the three remainders together , and extract the square root of the product.... | |
| John Groesbeck - 1891 - 426 pages
...tapers to a point. Find the value at 4^ cents per square foot. Ans. 63 cents. 447. To find the Area of a **Triangle when the Three Sides are given. Rule. —...half the sum of the three sides subtract each side** separately. Multiply the half sum and the three remainders together, and extract the square root of... | |
| Thomas Baker - 1891 - 264 pages
...has been made, and the work must be repeated. TO FIND THE AREA OF A TRIANGLE FROM THE THREE SIDES. **RULE. From half the sum of the three sides subtract each side severally** and reserve the three remainders ; multiply the half sum continually by the three remainders, and the... | |
| Horatio Nelson Robinson - 1892 - 430 pages
...50) -=- 2 = 60 ; 60 - 30 = 30 ; 60 - 40 = 20; 60 - 50 = 10. \X60~x30 x 20 x 10 = 600 sq. ft., area. **RULE. — From half the sum of the three sides subtract each side** separately; multiply the half-sum and the three remainders together; the square root of the product... | |
| Horatio Nelson Robinson - 1892 - 428 pages
...+ 50) -4- 2 = 60 ; 60 - 30 = 30 ; 60 - 40 = 20 ; 60 - 50 = 10. V60x30x20xlo' = 600 sq. ft. , area. **RULE. — From half the sum of the three sides subtract each side** separately ; multiply the half-sum and the three remainders together; the square root of the product... | |
| Massachusetts - 1893 - 986 pages
...given. Rule. — Take one-half the product of the side and perpendicular, and divide by 160. (ft) When **three sides are given. Rule. — From half the sum of the three sides subtract each side** separately ; multiply the half sum and the three remainders together; the square root of the product... | |
| William Kent - 1895 - 1244 pages
...altitude. RULE a. Multiply half the product of two sides by the sine of the Included angle. Ri'LE 3. **From half the sum of the three sides subtract each side severally; multiply** together the half sum and the three remainders, and extract the square root of the product. The area... | |
| Peder Lobben - 1899 - 460 pages
...circle of the same area. To Figure the Area of Any TriangIe when Only the Length of the Three Sides is **Given. RULE. From half the sum of the three sides subtract each side** separately ; multiply these three remainders with each other and the product by half the sum of the... | |
| William Whitehead Rupert - 1900 - 148 pages
...God, for which reason He always is God." CHAPTER V. THE AREA OF A TRIANGLE IN TERMS OF ITS SIDES. 48. **RULE. — From half the sum of the three sides subtract each side** separately ; multiply together the half sum and the three remainders and extract the square root of... | |
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