 | 1818 - 264 pages
...terms. 4. The comtnpn difference. 5. The sum of all the terms. PROBLEM I. The first term, the last term, and the number of terms being given, to find the sum...the terms. RULE. Multiply the sum of the extremes by the number of terms,," and half the product will be the answer. EXAMPLES. 1. The first term of an arithmetical... | |
 | George G. Carey - 1818 - 602 pages
...three of face being given, the other two may l»e foiled. st: L THE LEAST TERM, THE GREATEST TERM, AND THE NUMBER OF TERMS BEING GIVEN, TO FIND THE SUM OF ALL THE TERMS. RULE. Multiply the sum *f tbe greatest a*4 least terns by half the number of tersw, or by tbe whole jtumber of terms, anil... | |
 | James Maginness - 1821 - 378 pages
...common difference? By formula 1, per table, 3JL=3 = 2. Ans. PROBLEM 2. The first term, the last term, and the number of terms, being given, to find the sum of all the terms. The extremes of an arithmetical series are 3 and 39, and the number of terms 19; required, the sum... | |
 | Nicolas Pike - 1822 - 536 pages
...may be 37 miles : Required the daily increase ? » Ans. 4. PROBLEM If. Tie first term, the last term, and the number of terms being given, to find the sum of all the terms. • RuLE.t Multiply the sum of the extremes by the number of terms, and half the product will be the... | |
 | Zadock Thompson - 1826 - 176 pages
...difference, and the sum of all the terms. Problem I. The first term, the last term, and the number of terms given, to find the sum of all the terms. RULE.* — Multiply the sum of the extremes by the number of terms, and half the product will be the answer. Examples. 1. The first term of an arithmetical... | |
 | Roswell Chamberlain Smith - 1827 - 216 pages
...diminishes. PROBLEM I. — The first term, the last term, (ie the two extremes) and the number of terms given to find the sum of all the terms. RULE. — Multiply the sum of the extremes by half the num. Чег of terms, the product will be the answer. EXAMPLES. — How many times does a clock strike... | |
 | Daniel Parker - 1828 - 358 pages
...found. PROBLEM I. The first term, the last term, and the number of terms being given, to find the stun of all the terms. RULE. Multiply the sum of the extremes by the number of terms, and half the product will be the sum of the terms. Examples. 53+5=68 The sum of... | |
 | William Kinne - 1829 - 246 pages
...4th. The common difference. 5th. The sum of all the terms. PROBLEM 1. The first term, the last term, and the number of terms being given, to find the sum of all the terms. HOLE. — Multiply the sum of the extremes by the number of terms, and half the product will be the... | |
 | Nathan Daboll - 1829 - 268 pages
...first and last terms of which are called the extremes." PROBLEM I. » The first term. the iast term, and the number of terms being given, to find the sum of aL the terras. * .9 series in progression incltnles Jii-e par«- viz. th& jint term, last term, nitmbar... | |
 | William Kinne - 1831 - 248 pages
...4th. The common difference. 5th. The sum of all the terms. PROBLEM 1. The jirst term, the last term, and the number of terms being given, to find the sum of all the terms. RULE.—Multiply the sum of the extremes by the number of terms, and half the product will be the answer.... | |
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PROBLEM I. The first term, the last term, and the number of terms being given, to find the sum of all the terms. 
