 | James Elliot - 1879 - 118 pages
...1. Mean diam. of ring = 1. Content? PROBLEM XVIII. To find the Solid Content of a Spheroid (ACBD). RULE. Multiply the square of the revolving axis by the fixed axis and the product again by •5236 - . FORMULA. S= •ffi2 x F x - . o R being the revolving axis, and F the fixed axis.*... | |
 | Stephen Roper - 1884 - 740 pages
...the height ; multiply the sum by the height and by 1-5708. To find the cubic contents of a spheroid, multiply the square of the revolving axis by the fixed axis and by '5236. To find the cubic contents of a segment of a spheroid. — When the base is parallel to the... | |
 | Frank Eugene Kidder - 1886 - 640 pages
...the zone; multiply this sum by the height, and that Fig 42. product by 1.5708. To compute the volume of a spheroid. RULE. — Multiply the square of the revolving axis by the fixed axis, and this product by 0.5236. To compute the volume of a paraboloid of revolution (Fig. 43). RULE. — Multiply... | |
 | Daniel Kinnear Clark - 1889 - 1030 pages
...height; multiply the sum by the height, and by i'57o8. To find the cubic contents of a spheroid. — Multiply the square of the revolving axis by the fixed axis and by '5236. Note. — The contents of a spheroid are two-thirds of the contents of its circumscribing... | |
 | Frank Eugene Kidder - 1892 - 1032 pages
...this sum by the height, and that Fig. 42. product by 1.5708. To compute Ike volume of a xpheroiil. RULE. — Multiply the square of the revolving axis by the fixed axis, and this product by 0.5230. To compute the volume of a paraboloid of revolution (Fig. 43). RULE. — Multiply... | |
 | Frank Eugene Kidder - 1892 - 1058 pages
...by the height, and that Fig. 42. product by 1.5708. To compute the volume of a xpheroid. RULK. — Multiply the square of the revolving axis by the fixed axis, and this product by 0.5230. To compute the volume of a paraboloid of revolution (Fig. 43). RUI.K. — Multiply... | |
 | John Kelley Ellwood - 1892 - 300 pages
...diameter by 3.1416, and this by the proportionate height of the segment. 39. Volume of a Spheroid. — Multiply the square of the revolving axis by the fixed axis, and this product by .5236. 40. Volume of the Middle Frustum of a Spheroid (when ends are circular) . —... | |
 | Frederick Thomas Hodgson - 1904 - 370 pages
...remainder by the square of the height, and the product by the decimal .5236. OF SPHEROIDS Problem XI. — To find the solidity of a spheroid. Rule. — Multiply...revolving axis by the fixed axis: and the product, multiplied by .5236, will give the solidity. c Example. — What is thesolidity of an oblong spheroid,... | |
 | Frederick Thomas Hodgson - 1917 - 696 pages
...remainder by the square of the height, and the product by the decimal .5236. OF SPHEROIDS Problem XI. — To find the solidity of a spheroid. Rule. — Multiply...revolving axis by the fixed axis: and the product, multiplied by .5236, will give the solidity. c Example. — What is the solidity of an oblong spheroid,... | |
 | William Miller Barr - 1918 - 650 pages
...and this sum multiplied by the said breadth, and the product again by 1.5708, will give the solidity. To Find the Solidity of a Spheroid. — Rule: Multiply the square of the revolving axe by the fixed axe, and this product again by .5236, and it will given the solidity required. Where... | |
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To find the solidity of a spheroid. Rule. — Multiply the square of the revolving axis by the fixed axis: and the product, multiplied by .5236, will give the solidity. 
