 | James Thompson - 1808 - 176 pages
...feet, and one side of the equilateral end \\ feet ? Ans. 17.50859 ft. IV. Toßnd the solidity of a cylinder. RULE — Multiply the area of the base by the perpendicular height, and tke product will be the solidity. EXAMPLES. 7' What is the solidity of the cylinder, the diameter of... | |
 | Thomas Keith - 1817 - 306 pages
...solid yards of earth are contained in this part? Ans. 9000 yards. PROBLEM IV. To find the Solidity of a Cylinder *. RULE. Multiply the area of the base, by the perpendicular height of the cylinder, and the product will be the solidity. Note. * Rules might here be inserted for finding... | |
 | Anthony Nesbit - 1824 - 476 pages
...the area of the four sides is 3985.603941 square feet. PROBLEM vII. To find the solidity of a cone. RULE. Multiply the area of the base by the perpendicular height, and I of the product will be the solidity. Note t. The altitude of an oblique cone, or one whose axis do»'8... | |
 | Zadock Thompson - 1826 - 176 pages
...the largest squared stick of timber that can be hewn from it ? -/8X 8X2=11.31 in. Ans. Problem IV. To find the solidity of a prism, or cylinder. RULE. — Multiply the area of the end by the length of the prism, for the content. Examples. 1. What is the content of a triangular prism,... | |
 | Zadock Thompson - 1828 - 230 pages
...smallest end heing 24 inclies, how large square will the stick of timher hew ? Ans. 16.97 in. 318. To find the solidity of a prism, or cylinder. RULE. — Multiply the area of the end hy the length of the prism, " 2. What namher of cuhic feet in around stick of timher whnse diameter... | |
 | Thomas Curtis - 1829 - 810 pages
...too simple to need any formal statement. PROB. XXVI. To find the solid content of a cone or pyramid. Rule.— Multiply the area of the base by the perpendicular height, and one-third of the product will be the solidity. This rule is demonstrated in the article GEOMETRY. Example.—... | |
 | John Bonnycastle - 1829 - 256 pages
...feet 4 inches, and its length 14 feet. Ans. 116.666, 4-0. feet. PROBLEM V. To find the solidity of a cylinder. RULE.* Multiply the area of the base by the perpendicular height of the cylinder, and the product will be the solidity.' * The four following cases contain all the... | |
 | William Ruger - 1832 - 282 pages
...whose bases are circles, Ijke a round column or stick of timber, . of equal bigness from end to end. RULE — Multiply the area of the base by the perpendicular height, and the product will be the solidity. .EXAMPLES. 1. What is the solidity of a cylinder, the height of which 4$ 5 feet, and the diameter of... | |
 | Zadock Thompson - 1832 - 186 pages
...the side of the largest squared stick of timber that can be hewed from it? ^8X8X2=11.31 in. Ans. 318. To find the solidity of a prism, or cylinder. RULE. — Multiply the area of the end by the length of the prism, for the content. 1. What is the content of a triangular prism, the... | |
 | Ireland commissioners of nat. educ - 1834 - 370 pages
...Ans. 2-756 inches in length will make one solid foot. PROBLEM III. To find the solidity of a prism. RULE. Multiply the area of the base by the perpendicular...height and the product will be the solidity. Note. The reason of this rule ia evident from what was said in Rule I. 1. What is the solidity of a prism,... | |
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Rule. — Multiply the area of the base by the perpendicular height, and the product will be the solid contents. 
