 | David Steel - 1805 - 392 pages
...intersecting in the several points k, through which the hyperbolic curve is to be drawn. PROBLEM 11. To find the Solidity of a Spheroid. RULE. Multiply...square of the revolving axis by the fixed axis, and multiply the product by .5236 for the solid content. EXAMPLE. Required the content of a prolate spheroid,... | |
 | Thomas Keith - 1817 - 306 pages
...i«N or vn 80 inches ? Ans. 174830'9116 cubic inches, or 620' l 8052 gallons. PROBLEM XVIII. Tofiud the Solidity of a Spheroid. RULE *. Multiply the square of the revolving axis by the fixed axis, and this product again by •5236, the last product will be the solidity. Example 1 . Let A cu E be a prelate... | |
 | William Hawney - 1820 - 336 pages
...is called the revolving axis,, and the shorter axis is called the fixed axis. To find the Solidity, RULE. Multiply the square of the revolving axis by the fixed axis, and that product by .5236 for the soHdity. '/ EXAMPLES. 1. Let AD6C be a prolate spheroid, whose longer... | |
 | Anthony Nesbit - 1824 - 476 pages
...Conic Sections, are referred to the works of Emerson, Hutton, and Simson en that subject. PROBLEM XI. To find the solidity of a spheroid. RULE. Multiply...revolving axis by the fixed axis, and the product thence arising by .5236 ; and the last product will be the solidity. Kale 1. The multiplier .5U6 is... | |
 | William Galbraith - 1827 - 412 pages
...0.618034 11 Undecagon 9.3656399 1.7747324 0.563465 12 Dodecagon 11.1961524 1.9318517 0.517638 Capacity. Multiply the square of the revolving axis by the fixed axis, and the product by 0.5236, the result will be the content. 8. Regular, or Platonic bodies, as they are sometimes called,... | |
 | Thomas Curtis - 1829 - 810 pages
...6-2832, for the solidity. Рвов. XXXVI. To find the solidity of a spheroid, its two ares being given. Rule. — Multiply the square of the revolving axis by the fixed axis, and the product again by 5236 for the solidity. PROB. XXXVII. To find the solidity of the middle fruition of a spheroid,... | |
 | John Bonnycastle - 1829 - 256 pages
...h and H — k=a, we fl~ HO shall have (I{2_|_j.2_| -- \ Xi_ ; which is the rule. 3 ii PROBLEM XVI. To find the solidity of a spheroid. RULE.* Multiply the square of the revolving axe by the fixed axe, and this product again by .5236, and it will give the solidity required. Where... | |
 | William Templeton (engineer.) - 1833 - 224 pages
...24* x 3= 1728, then 1728+625 x 25 x .5236=30800.77 277.274 = 1 1 1.084 gallons nearly. PROBLEM IX. To find the Solidity of a. Spheroid. RULE. — Multiply...square of the revolving axis by the fixed axis, and by .5236, and the product will be the solidity. - . EXAMPLE 1.— Required the solid content of the... | |
 | William Galbraith - 1834 - 454 pages
...content. 7- Spheroid, or solid formed by the revolution of an ellipse about one of its axes. Capacity. Multiply the square of the revolving axis by the fixed axis, and the product by 0.5236, the result will be the content. 8. Regular, or Platonic bodies, as they are sometimes called,... | |
 | Ireland commissioners of nat. educ - 1834 - 370 pages
...gallons is 96-7608, allowing 282 cubic inches to the ale gallon. PROBLEM XVIII. Toßnd the solidity of-a spheroid. RULE. Multiply the square of the revolving axis by the fixed axis, and this product again by -5236 for the solidity.* 1. What is the solidity of a prolate spheroid whose... | |
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To find the solidity of a spheroid. Rule. — Multiply the square of the revolving axis by the fixed axis: and the product, multiplied by .5236, will give the solidity. 
