Rudimentary treatise on mensuration and measuring |
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Page 16
... axis produced . So shall F be what is called the focus . Draw several double ordinates SRS & c . , perpendicular to V P. Then with the radii C R , & c . and the centre F , describe arcs cut- ting the corresponding ordinates in the ...
... axis produced . So shall F be what is called the focus . Draw several double ordinates SRS & c . , perpendicular to V P. Then with the radii C R , & c . and the centre F , describe arcs cut- ting the corresponding ordinates in the ...
Page 31
... axis TR , the conjugate axis CO , the abscissa HQ , and the ordinate PQ . FORMULE . Put a semitransverse = HR , b = semiconjugate x = abscissa a x = - √ b2 —y3 , y = CH . = H Q , and y = ordinate = PQ ; then b C P = - √a2 - x2 , α ...
... axis TR , the conjugate axis CO , the abscissa HQ , and the ordinate PQ . FORMULE . Put a semitransverse = HR , b = semiconjugate x = abscissa a x = - √ b2 —y3 , y = CH . = H Q , and y = ordinate = PQ ; then b C P = - √a2 - x2 , α ...
Page 32
... axes being 7926 and 7899 miles . Ans . 654 miles , or 327 miles each from the earth's centre . PROBLEM X. The axes of an ellipse are given to find its circumference . RULE I. - Multiply half the sum of the two axes by 3.1416 , and the ...
... axes being 7926 and 7899 miles . Ans . 654 miles , or 327 miles each from the earth's centre . PROBLEM X. The axes of an ellipse are given to find its circumference . RULE I. - Multiply half the sum of the two axes by 3.1416 , and the ...
Page 48
... axes . ( See last figure . ) RULE . - Divide the height of the segment by that axis of the ellipse of which it is a part ; and find in the table of circular segments at the end of the book , a circular segment having the same versed ...
... axes . ( See last figure . ) RULE . - Divide the height of the segment by that axis of the ellipse of which it is a part ; and find in the table of circular segments at the end of the book , a circular segment having the same versed ...
Page 49
... axis , the height being 5 , and the axes 25 and 35 feet ? Ans . 97.8458 square feet . PROBLEM XIV . To find the area of a parabola . RULE . - Multiply the axis or height VE by the base or double ordinate D F , and of the product will be ...
... axis , the height being 5 , and the axes 25 and 35 feet ? Ans . 97.8458 square feet . PROBLEM XIV . To find the area of a parabola . RULE . - Multiply the axis or height VE by the base or double ordinate D F , and of the product will be ...
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Common terms and phrases
12 feet 20 feet A B C AMEN CORNER axis Baker's Land base bottom width centre chains Charles Tomlinson chord circle circular circumference content in cubic correction for curvature cubic feet cubic foot cubic yards curve decagon decimals depths diagonal diameter distance Duodecimals Engineering Surveying equal EXAMPLES feet 6 inches feet long figure find the area find the content find the solidity foot fore sights formula frustrum given ground half height instrument Land and Engineering length level book measured method miles multiply NOTE offsets parabola perpendicular polygon Prob PROBLEM pyramid quantity quarter girt radius railway cutting refraction required the area Required the content RULE RULE.-Multiply S. P. Woodward screws segment side slopes SLIDING RULE spirit level square feet square yards staves subtract Table tangent telescope trapezium VIRTUE BROTHERS W. D. Hamilton zone
Popular passages
Page 3 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; and each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds ; and these into thirds, &c.
Page 51 - The sphere may be conceived to be formed by the revolution of a semicircle about its diameter, which remains fixed.
Page 5 - Is. 6d. 76. GEOMETRY, DESCRIPTIVE, with a Theory of Shadows and Perspective, and a Description of the Principles and Practice of Isometrical Projection, by JF Heather.
Page 51 - A sphere is a solid bounded by a curved surface, every point of which is equally distant from a point within called the center.
Page 4 - SHIP-BUILDING AND NAVIGATION. 51. NAVAL ARCHITECTURE, by J. Peake. 3s. 53*. SHIPS FOR OCEAN AND RIVER SERVICE, Construction of, by Captain HA Sommerfeldt. Is. 53**.
Page 145 - EMIGRANT'S GUIDE TO TASMANIA AND NEW ZEALAND, by James Baird, BA [In Preparation. FINE ARTS. 20. PERSPECTIVE, by George Pyne. 2s. 27. PAINTING ; or, A GRAMMAR OF COLOURING, by G. Field. 2s. 40. GLASS STAINING, by Dr. MA Gessert, with an Appendix on the Art of Enamel Painting, &c.
Page 81 - Large and plain articles are usually measured by the square foot or yard, &c; but enriched mouldings, and some other articles, are often estimated by running or lineal measure •, and some things are rated by the piece. In measuring of Joists...
Page 86 - GLAZIERS' WORK. — Glaziers take their dimensions either in feet, inches, and parts ; or feet, tenths, and hundredths. And they compute their work in square feet. In taking the length and breadth of a window, the cross bars between the squares are included. Also, windows of round or oval forms are measured as square, measuring them to their greatest length and breadth, on account of the waste in cutting the glass.