A Treatise of Practical Mathematics, Part 2W. & R. Chambers, 1842 |
From inside the book
Results 1-5 of 88
Page 11
... preceding , from the measurements given in the subjoined field - book . Ans . 0 ac . 3 ro . 39.72 pls . Left Offsets . Chain Line . Right Offsets . 368 to 04 328 44 144 40 From 01 to L of 02 ) ) to river 260 to 01 168 20 to gate 52 24 ...
... preceding , from the measurements given in the subjoined field - book . Ans . 0 ac . 3 ro . 39.72 pls . Left Offsets . Chain Line . Right Offsets . 368 to 04 328 44 144 40 From 01 to L of 02 ) ) to river 260 to 01 168 20 to gate 52 24 ...
Page 15
... preceding exercise , were as below : — AO 4315 links - OB = 2982 OC = 3561 OD = 5010 OE = 4618 OF 3606 = What is the area ? ... ... ... Angle AOB 60 ° 30 ′ ... BOC47 ° 40 ' COD 49 ° 50 ' = DOE 57 ° 10 ' - EOF 64 ° 15 ' = FOA 80 ° 35 ...
... preceding exercise , were as below : — AO 4315 links - OB = 2982 OC = 3561 OD = 5010 OE = 4618 OF 3606 = What is the area ? ... ... ... Angle AOB 60 ° 30 ′ ... BOC47 ° 40 ' COD 49 ° 50 ' = DOE 57 ° 10 ' - EOF 64 ° 15 ' = FOA 80 ° 35 ...
Page 18
... preceding method , a field may be surveyed from two stations situated without the field , its area computed , and a plan of it made . SURVEYING WITH THE PLANE TABLE . 29. By means of the plane table a plan of a field or estate is ...
... preceding method , a field may be surveyed from two stations situated without the field , its area computed , and a plan of it made . SURVEYING WITH THE PLANE TABLE . 29. By means of the plane table a plan of a field or estate is ...
Page 20
... fields according to any of the methods in the three preceding problems , fix on a station in this field , whose position is known on the paper , and take some station in the adjoining field at a sufficient 20 PRACTICAL MATHEMATICS .
... fields according to any of the methods in the three preceding problems , fix on a station in this field , whose position is known on the paper , and take some station in the adjoining field at a sufficient 20 PRACTICAL MATHEMATICS .
Page 23
... h 1240 = 822.6 links = AP . EXERCISE . Cut off from a triangular field , as in the preceding exercise , a part containing 2 acres 1 rood 24 poles , the length of one side of the triangle being 1280 links , and the LAND - SURVEYING . 23.
... h 1240 = 822.6 links = AP . EXERCISE . Cut off from a triangular field , as in the preceding exercise , a part containing 2 acres 1 rood 24 poles , the length of one side of the triangle being 1280 links , and the LAND - SURVEYING . 23.
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Common terms and phrases
actual range bastion body breadth bung diameter called cask centre constructed content in imperial cosec cosine course declination deflexion depth dial difference of latitude difference of longitude distance ditch divide divisor draw earth elevation equal EXAMPLE EXERCISES fathoms Find the content flank frustum gauge point glacis hence horizontal hypotenuse imperial bushels imperial gallons impetus inches inclination length logarithms longitude mean diameter measure meridian middle moon's multiply number of balls oblique observed opposite parallax parallel parapet perpendicular pile place of arms plane plane sailing pole potential range preceding primitive PROBLEM projectile projection proportional quadrant quotient radius ravelin redoubt refraction right angle right ascension sailing semi-diameter Severndroog Castle side sidereal sin² sine Sliding Rule small circle specific gravity spherical angle spherical excess spherical triangle spherical trigonometry square sun's surface true altitude ullage velocity vessel weight
Popular passages
Page 196 - Fig. 9. Case 1. Let AB, AC be each less than a quadrant. Let AE, AG be quadrants ; G will be the pole of AB, and E the pole of AC, and EC a quadrant; but, by prop. 12. CE is greater than CB, since CB is farther off from CGD than CE. In the same manner, it is shown...
Page 95 - To the square of the bung diameter add the square of the head diameter ; multiply the sum by the length, and the product again by .0014 for ale gallons, or by .0017 for wine gallons.
Page 96 - RULE. — To the square of the bung diameter add the square of the head diameter ; multiply the sum by the length, and the product by .0014 for ale gallons, or by .0017 for wine gallons.
Page 42 - A magnitude which has length, breadth, and thickness. Solution. The process by which the answer to a question is obtained. Specific gravity of a substance. The ratio of the weight of a given volume of it to that of an equal volume of water.
Page 192 - A sphere is a solid, bounded by one continued convex surface, every point of which is equally distant from a point within, called the centre. The sphere may be conceived to be formed by the revolution of a semicircle about its diameter, which remains fixed.
Page 227 - ZODIAC.— The Zodiac is an imaginary belt, or broad circle, extending quite around the heavens. The ecliptic divides the zodiac into two equal parts, the zodiac extending 8 degrees on each side of the ecliptic, and therefore is 16 degrees wide.
Page 196 - BC will be greater than a quadrant : for let AE be a quadrant, then E is the pole of AC, and EC will be a quadrant. But CB is greater than CE by Prop. 12.
Page 195 - Oj the same affection with the angles opposite to them, that is, if the sides be greater or less than quadrants, the opposite angles will be greater or less than right angles, and conversely.
Page 195 - IN a right angled spherical triangle, the sides are of the same affection with the opposite angles ; that is, if the sides be greater or less than quadrants, the opposite angles will be greater or less than right angles. Let ABC be a spherical triangle right angled at A, any side AB, will be of the same affection with the opposite angle ACB. Case 1.
Page 195 - ... will be greater than a quadrant. Let ABC be a right angled spherical triangle ; according as the two sides AB, AC are of the same or of different affection, the hypotenuse BC will be less, or greater than a quadrant. The...