| William Taylor (teacher of the mathematics.) - 1800 - 556 pages
...of the bafe, add the fquare of the middle diameter, between the bafe and the vertex ; and this fum multiplied by the altitude, and the product again by ,5236, will give the folidity. ,* E. j. In the Hyperboloid ABC, the altitude Ь is 20, the radius с С of the bafe 24,... | |
| Anthony Nesbit, W. Little - 1822 - 916 pages
...met with in Practice ; if, however, they should occur, their contents may be found by the following Rule : To the square of the radius of the base add the square of the diameter taken in the middle between the base and the vertex ; then this sum being multiplied by the... | |
| Anthony Nesbit - 1824 - 476 pages
...and wine gallons ? Ans. 40.7071 ale, and 4<M>944 wine gallons. PROBLEM XIX. To find the solidity of a hyperboloid. RULE. To the square of the radius of the base, add the square of the diameter in the middle between the base and the vertex ; then this sum being multiplied by the altitude,... | |
| John Bonnycastle - 1829 - 256 pages
...60, that of the less end 48, and the distance of the ends 18 ? Ans. 41733.0144. PROBLEM XXI. To find the solidity of an hyperboloid. RULE.* To the square...the product again by .5236, will give the solidity. Btl ment is 4 AB — %db. But B — b : A. — a (d) : : B : A= ~; bd and B — 6 : d :: b : a= -by... | |
| Tobias Ostrander - 1833 - 172 pages
...that of the less 50, and the distance of the ends 101 Ans. 23954,7 solidity required. PROBLEM XVII. the middle diameter between the base and the vertex, and this sum multiplied by the altitude, and that product by ,5236, the last product will give the solidity. EXAMPLES. 1. In the hyperboloid the... | |
| Tobias Ostrander - 1834 - 182 pages
...the distance of the ends 10 ? Ans. 23954,7 solidity required. PROBLEM XVII. To find the solidity of a hyperboloid. Rule — To the square of the radius...vertex, and this sum multiplied by the altitude, and that product by ,5236, the last product will give the solidity. EXAMFLfiS. 1. In the hyperboloid the... | |
| John Bonnycastle - 1835 - 308 pages
...60, that of the less end 48, and the distance of the ends 18? Ans. 41733.0144. PROBLEM XXI. To find the solidity of an hyperboloid. RULE.* To the square...by .5236, will give the solidity. sd ment is £ AB — %ab. But B — b : A — a (d) : : B : A= — — j? bd and B — b : d : : b : a= — vby the... | |
| Thomas Holliday - 1838 - 404 pages
...inches. Answer, 41733.0144 inches. PROBLEM XIV. TO FIND THE SOLIDITY OF AN HYPERBOLIC CONOID. Rule.—To the square of the radius of the base, add the square...the product again by .5236 will give the solidity. Examples. In the hyperboloid ACS, the altitude n—C being 16, the radius A—n of the base 20, and... | |
| Charles Davies - 1840 - 264 pages
...PROBLEM X. 11. To find the solidity of a spherical segment with one base. RULE. 1st. To three times the square of the radius of the base add the square of the height. 2d. Multiply this sum by the height, and the product by the decimal ,5236 : the result will... | |
| John Bonnycastle - 1842 - 318 pages
...60, that of the less end 48, and the distance of the ends 18? Ans. 41733.0144. PROBLEM XXI. Tojind the solidity of an hyperboloid. RULE.* To the square...again by .5236, will give the solidity. sd ment is J AB — %ab. But B — b : A — a (d) : : B : \= - — •%; Id and B — b : d :: b : a— — -rby... | |
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