| Charles Hutton - 1770 - 518 pages
...trapezoide will be infinite, and it is then called, fometimes, a cylindroid. GENERAL RULE. To the fum **of the areas of the two ends add four times the area of a** fection parallel to and equally diftant from both ends, multiply the laft fum by the height and i of... | |
| John McGregor (teacher of mathematics.) - 1792 - 431 pages
...being 72 feet. Anf. 89.5356 cubit-feet. , PROBLEM IX. Tcjlnd the folidity of the prifmoid. RULE I. To **the areas of the two ends add four times the area of** the middle feâion. Multiply the fum by the height, and $ the produft will be the folidity. RULE 2.... | |
| Thomas Keith - 1817 - 304 pages
...*2618 (one-third of '7854), and then by the height, the last product will be the solidity. RULE II*. To **the sum of the areas of the two ends, add four times the area of a section parallel to.** * The first Rule, which is the same is that given for the priimoid, wai introduced into this work by... | |
| Anthony Nesbit, W. Little - 1822 - 916 pages
...bushels. PROBLEM IX. 'To find the content of a vessel in the form of a prismoid, RULE, By the Pen. To **the sum of the areas of the two ends, add four times the area of a section parallel to,** and equally distant from both ends ; multiply this sum by the perpendicular depth, and $ of the product... | |
| Anthony Nesbit - 1824 - 476 pages
...or the frustum of a square pyramid ; to find its. content in ale and wine gallons, ana matt bus/ids. **RULE. To the sum of the areas of the two ends add four times the area of** the middle section parallel t» them ; multiply this sum by the perpendicular depth, and J of the product... | |
| Thomas Curtis - 1829 - 812 pages
...9 ,4/1 ~ = 7140 solid inches, or 4-1319 solid feet. PROB. XXIX. To find the solidity of a promoid. **Rule,— to the sum of the areas of the two ends add four times the area of a section parallel to,** and equally distant from, both ends, and multiply the sum by one-tenth of the height for the solidity.... | |
| John Bonnycastle - 1829 - 252 pages
...perpendicular height to be 17.14508 inches ? Ans. 3.1006 feet. PROBLEM XI. To find the solidity ofaprismoid. . **RULE.* To the sum of the areas of the two ends add four times the area of a section parallel** tq and equally distant from both ends, and this last sum multiplied by £ of the height will give the... | |
| Thomas Curtis - 1829 - 878 pages
...in many cases it gives very erroneous results. The true method of finding the solidity is this : to **the sum of the areas of the two ends, add four times the area of** the middle section between them, and the sum multiplied by onelixth of the length will give the solidity.... | |
| John Bonnycastle - 1833 - 310 pages
...perpendicular height to be 17. 14508 inches? Ans. 3.1006/ee<. PROBLEM XI. To find the solidity of a primoid. **RULE.* To the sum of the areas of the two ends add four times the area of a section parallel to** and equally distant from both ends, and this last sum multiplied by £ of the height will give the... | |
| Jeremiah Day - 1831 - 418 pages
...what is the solidity ? Ans. 5040. PROBLEM VIII. Tofint} the SOLIDITY of a rectangular PRISMOID. 55. To **THE AREAS OF THE TWO ENDS, ADD FOUR TIMES THE AREA OF A** PARALLEL SECTION EQUALLY DISTANT FROM THE ENDS, AND MULTIPLY THE SUM BY i OF THE HEIGHT. Let L and... | |
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