Ex.-Required the weight of one lineal foot of inch thick, and 24 inches broad. malleable iron, 2·25 × ·5=1·125 × 1 × 1·125 × 3·32–3·735 lbs. or 3 lbs. 11.76 oz But for the sake of expedition these Tables have been constructed as follows. Having found by the above rule, the weight of one lineal foot for 4th of an inch according to the thickness, it has been constantly added until the breadth has attained to one foot. •125=1, then Example. •125 x 125·015625 × 3·32=05187500 lbs. × 16='83 oz. N.B. The Tables advancing by of an inch in breadth are constructed in the same manner as the above. SHOWING THE WEIGHT OF A LINEAL FOOT OF ROUND BAR IRON, in Avoirdupois qrs. tbs. oz., from th of an Inch to 12 Inches Diameter, advancing by th of an Inch. SHOWING THE WEIGHT OF A LINEAL FOOT OF SQUARE BAR IRON, in Avoirdupois qrs. tbs. oz., from th of an Inch to 12 Inches, advancing by th of an Inch. OBSERVATIONS ON TABLES III. AND IV. The Tables of the weight of round and square bars of malleable iron have been obtained by the following approximate rules : Rule 1.-For round bars. Multiply the square of the diameter in inches by the length in feet, and that product by 2.6. The product will be the weight in pounds avoirdupois, nearly. Rule 2.-For square bars. Multiply the area of the end of the bar in inches by the length in feet, and that by 3:32. The product will be the weight in pounds avoirdupois, nearly. Example 1.-What is the weight of a round bar of malleable iron 43 feet long, and 24 inches in diameter? 2.252 × 4.5=22.78125 × 2·6=59.23125 lbs.=59 lbs. 3.7 oz. Example 2.-Required the weight of a square bar of malleable iron whose length is 7 feet, and 11 inch square. 1.52 x 7.25=16·3125 × 3·32=54.1575 lbs.=54 lbs. 2.52 oz. J. F. |