 | William Templeton (engineer.) - 1833 - 224 pages
...181 nearly, as before. PROBLEM II. To find the Surface and Solid Content of a Cone or Pyramid. RULE 1. — Multiply the circumference of the base by the slant height, and half the product will be the slant surface, to which add the area of the base, and the product will be the whole surface.... | |
 | Luther Ainsworth - 1837 - 298 pages
...would cover the whole pyramid, if they were laid out 6 inches ? Ans. 4,063,620 shingles. NOTE. — Multiply the circumference of the base, by the slant height, and half the product will be the superficial area. ARTICLE IV. OF LATHING AND PLASTERING. \ Q. How are Laths estimated in... | |
 | Charles Haynes Haswell - 1844 - 298 pages
...the Convex Surface of a Right Cone or Pyramid— figs. 31 and 33. RULE. — Multiply the perimeter or circumference of the base by the slant height, and half the product added to the area of the base will be the surface. To find the Convex Surface of a Frustrum of a Right... | |
 | William Templeton (engineer.) - 1845 - 210 pages
...feet, the length required. To find the convex surface, solidity, or capacity of a cone or pyramid. Rule 1 . — Multiply the circumference of the base by...area of the base by the perpendicular height, and one-third of the product is the solidity or capacity, as may be required. Application of the rules.... | |
 | Thomas Kelt - 1849 - 424 pages
...the length required. To find the convex surface, solidity, or capacity of a cone or pi/ramid. Rule 1. — Multiply the circumference of the base by the...height, and half the product is the slant surface. Ruk 2. — Multiply the area of the base by the perpendicular height, and one third of the product... | |
 | Charles Haslett - 1855 - 482 pages
...5'76895 feet in depth. PROBLEM IH. To find the surface and mlid content of a cone or pyramid. RULE 1. Multiply the circumference of the base by the slant height, and half the product will be the slant surface ; to which add the area of the base, and the product -will be the whole surface.... | |
 | William Templeton (engineer.) - 1855 - 326 pages
...surface, solidity, or capacity of a cone or pyramid. Rule 1. — Multiply the circumference of the hase by the slant height, and half the product is the slant surface. Mule 2. — Multiply the area of the base by the perpendicular height, and one-third of the product... | |
 | Charles W. Hackley - 1856 - 530 pages
...materials, of which to be j PROBLEM III. Tojind the surface and solid content of a cone or pyramid. RULE 1. Multiply the circumference of the base by the slant height, and half the product will be the slant surface; to which add the area of the base, and the product will be the whole surface.... | |
 | Charles Haslett - 1855 - 544 pages
...to be j constructed, PROBLEM III. To find the surface and solid content of a cone or pyramid. RULE 1. Multiply the circumference of the base by the slant height, and half the product will be the slant surface; to which add the area of the base, and the product will be the whole surface,... | |
 | 1855 - 420 pages
...feet, the length required. To find the convex surface, solidity, or capacity oj a cone or pyramid. Rule 1. — Multiply the circumference of the base by the...or capacity, as may be required. Application of the Rules. 1. Required the area, in square inches, of the slant surface of a cone whose slant height equal... | |
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To find the convex surface, solidity, or capacity oj a cone or pyramid. Rule 1. — Multiply the circumference of the base by the slant height, and half the product is the slant surface. 
