A Treatise on Trigonometry, Plane and Spherical: With Its Application to Navigation and Surveying, Nautical and Practical Astronomy and Geodesy : with Logarithmic, Trigonometrical, and Nautical TablesG.P. Putnam, 1852 - 496 pages |
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Page 27
... hypothenuse of the triangle does to the side opposite the acute angle . It is customary , for conciseness , to represent the sides opposite the angles of a triangle by small letters of the same name with the large let- ters which are ...
... hypothenuse of the triangle does to the side opposite the acute angle . It is customary , for conciseness , to represent the sides opposite the angles of a triangle by small letters of the same name with the large let- ters which are ...
Page 29
... hypothenuse is required . Formula ( 1 ) of the last article applied to this case gives * 1 : sin 350 : a : 15 Multiplying the extremes and dividing by the first mean the value of the other mean which is a , the hypothenuse required ...
... hypothenuse is required . Formula ( 1 ) of the last article applied to this case gives * 1 : sin 350 : a : 15 Multiplying the extremes and dividing by the first mean the value of the other mean which is a , the hypothenuse required ...
Page 30
... hypothenuse is equivalent to the sum of the squares upon the other two sides . Let the height of the roof be 12 feet , and the semi - breadth 16 feet , then whence , = a2 122162 : = 400 a = 20 If the length of the rafters had been given ...
... hypothenuse is equivalent to the sum of the squares upon the other two sides . Let the height of the roof be 12 feet , and the semi - breadth 16 feet , then whence , = a2 122162 : = 400 a = 20 If the length of the rafters had been given ...
Page 31
... hypothenuse not entering into the prob- lem , neither of the above formulas , all of which contain the hypothenuse , would serve to find the side required in a direct manner . It might , how- ever , be found indirectly by first finding ...
... hypothenuse not entering into the prob- lem , neither of the above formulas , all of which contain the hypothenuse , would serve to find the side required in a direct manner . It might , how- ever , be found indirectly by first finding ...
Page 54
... hypothenuse a = 1010 X 15 sin 35 ° employing 1010 as R , instead of 1 , because the tables which we are about to use are constructed with that value of R , we have , by the rules for multiplication and division of logarithms log . of ...
... hypothenuse a = 1010 X 15 sin 35 ° employing 1010 as R , instead of 1 , because the tables which we are about to use are constructed with that value of R , we have , by the rules for multiplication and division of logarithms log . of ...
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Common terms and phrases
altitude applied arith azimuth calculated called celestial sphere centre colatitude collimation column comp complement computed corresponding cos² cosc cosec cosine cot² cotangent decimal declination determine diagram diff divided employed equation error EXAMPLE expressed feet formula Geom given number half the sum height hence horizontal hour angle hypothenuse instrument latitude longitude means meridian middle wire miles multiplied Nautical Almanac negative number of degrees observed obtained parallel perpendicular plane triangle polar pole proportion quadrant quotient radius right angled triangle right ascension screw secant second member side opposite siderial sin a sin sin² sine and cosine sine of half solution sphere spherical triangle spherical trigonometry spirit level star substituting subtracting supporting axis supposed tables of Callet tangent telescope three sides transit trigonometrical lines vertex zenith distance