The complete measurer: or, The whole art of measuring, containing the substance of Hawney's Mensuration, newly arranged, adapted to the present improved state of science, and incorporated with a variety of original and important matter1817 |
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Page 5
... of which will be a Quadrant , or one - fourth of the circle . The line cn , drawn from the centre to the circumference , is called the Radius . B 3 35. A 35. A Sector of a circle is comprehended under two PRACTICAL GEOMETRY , 5.
... of which will be a Quadrant , or one - fourth of the circle . The line cn , drawn from the centre to the circumference , is called the Radius . B 3 35. A 35. A Sector of a circle is comprehended under two PRACTICAL GEOMETRY , 5.
Page 10
... radius , or opening of the com- passes , greater than half △ e , de- scribe two arcs cutting each other A- in c and D ; draw c D , and it will cut A B in the point E , making a 2 . equal to E B. PROBLEM II . At a given Distance E , to ...
... radius , or opening of the com- passes , greater than half △ e , de- scribe two arcs cutting each other A- in c and D ; draw c D , and it will cut A B in the point E , making a 2 . equal to E B. PROBLEM II . At a given Distance E , to ...
Page 13
... radius describe an arc r ; through m and n draw the line mnr to cut the arc in r ; then through r and P draw CP , and it will be the perpendicular required . A B Or thus : Set one foot of the compasses in e , and extend the other to any ...
... radius describe an arc r ; through m and n draw the line mnr to cut the arc in r ; then through r and P draw CP , and it will be the perpendicular required . A B Or thus : Set one foot of the compasses in e , and extend the other to any ...
Page 14
... radius nm , or n c , describe an arc cutting A B in 0 , draw co , and it will be the perpendicular required . PROBLEM X. In any Triangle ABC to draw Perpendicular from any Angle to its opposite Side . Bisect either of the sides con ...
... radius nm , or n c , describe an arc cutting A B in 0 , draw co , and it will be the perpendicular required . PROBLEM X. In any Triangle ABC to draw Perpendicular from any Angle to its opposite Side . Bisect either of the sides con ...
Page 15
... radius AC describe an arc , with the centre в and distance B C cross it in c , draw A C and B C , then A ABC is the triangle required . PROBLEM XIII . Two Sides A B and B C of a right angled Triangle being given , to find the ...
... radius AC describe an arc , with the centre в and distance B C cross it in c , draw A C and B C , then A ABC is the triangle required . PROBLEM XIII . Two Sides A B and B C of a right angled Triangle being given , to find the ...
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The Complete Measurer: Or, the Whole Art of Measuring, Containing the ... Thomas Keith,William Hawney No preview available - 2016 |
Common terms and phrases
16 feet 20 inches 9 inches abscissa arch Area Seg breadth bung-diameter cask centre chord A B circle circular circular segment circum circumference COMPLETE MEASURER cone conjugate axis conoid contained Cross hedge cubic inches curve depth diameter A B distance divided double ordinate ellipsis elliptical equal EUCLID Example feet 6 inches feet 9 figure find the Area find the Solidity foot frustum gauge-point given greater end head-diameter hence hyperbola inches broad latus rectum length less end measure multiply the sum Off-sets ounces parabola parallel parallelogram perpendicular perpendicular height polygon pounds Prob PROBLEM pyramid quarter girt quotient radius Required the area Required the solidity rhombus roof segment semicircle side slant height Sliding Rule solidity and superficies specific gravity sphere spheroid square root straight line subtract surface thickness timber transverse axis trapezium triangle vertex whole wine gallons yards zone
Popular passages
Page 47 - BAC is cut off from the given circle ABC containing an angle equal to the given angle D : Which was to be done. PROP. XXXV. THEOR. If two straight lines within a circle cut one another, the rectangle contained by the segments of one of them is equal to the rectangle contained by the segments of the other.
Page x - An INTRODUCTION to the THEORY and PRACTICE of PLANE and SPHERICAL TRIGONOMETRY, and the Stereographic Projection of the Sphere, including the Theory of Navigation ; comprehending a variety of Rules, Formulae, &c.
Page 37 - To find the area of a trapezoid. RULE. Multiply half the sum of the two parallel sides by the perpendicular distance between them : the product will be the area.
Page 3 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds.
Page 5 - A diameter of a circle is a straight line drawn through the centre, and terminated both ways by the circumference.
Page 101 - The Slant height of a regular pyramid is the distance from the vertex to the middle of one of the sides of the base, or, if it be a cone, to the circumference of the base.
Page 99 - To find the solidity of a cylinder. RULE. — Multiply the area of the base by the altitude, and the product will be the solidity.
Page 49 - ... multiply the square of the diameter by ,7854 and the product will be- the area.
Page 27 - The area of any figure is the space contained within the bounds of its surface. without any regard to thickness, and is estimated by the number of squares contained in the same ; the side of those squares being either an inch, a foot, a yard, a rod, &c.
Page 195 - Required the quantity of plastering in a room, the length being 14 feet 5 inches, breadth 13 feet 2 inches, and height 9 feet 3 inches to the under side of the cornice, which girts...