 | William Nicholson - 1809 - 722 pages
...add the sqnare of its height ; multiply the sum by the height, and the product by .r>'236.' Or, 2<Uy, From three times the diameter of the sphere, subtract twice the height of the fribtnim ; multiply the remaintier by the square of the height, and the product by .5236. SEGUIERIA,... | |
 | Charles Hutton - 1811 - 494 pages
...x |FI = v^fl« > and by the similar cones AST, QMI, as * E 2 52 MENSURATION or SOLIDS. take double the height of -the segment ; then multiply the remainder by the square of the height, and the product by the decimal -5436, for the content. RULE II. To 3 times the square of the radius of the segment's... | |
 | Charles Hutton - 1812 - 620 pages
...content of the cone ABI is= %ad* X $ TI = £. ad* ; and by the similar cones ABI, <IMI, u take double the height of the segment : then multiply the remainder by the square of the height, and the product by the decimal -5236, for the content. RULE II. To 3 times the square of the radius of the segment's... | |
 | Charles Hutton - 1815 - 686 pages
...the square of its height ; multiply the sum by the height, and the product by '5236. Or, 2dly, From 3 times the diameter of the sphere, subtract twice the height of the frustum ; multiply the remainder by the square of the height, and the product by '5236. That is, in... | |
 | Thomas Keith - 1817 - 306 pages
...tUe globe is the .greatest. PROBLEM XIII. Tojlnd the Solidity of the Segment of a Sphere. RULE 1 *. From three times the diameter of the sphere, subtract twice the height of the segment ; multiply * Demonstrauon. Let A cm represent a triangular pyramid, whose tide m A is infinitely small.... | |
 | William Nicholson - 1821 - 384 pages
...52J6. Or, 2dly, From three times the diameter of thesphere. subtract twice the height of the frustrum; multiply the remainder by the square of the height, and the product by .5236. SEGUIERIA, in botany, so named in honour of Jean Francois Seguier, u genus of the Polyandria... | |
 | William Nicholson - 1821 - 382 pages
...add the square of its height ; multiply the sum by the height, and the pioduct by .52J6. Or, 2dly, From three times the diameter of the sphere, subtract twice the height of the frustrum; multiply the remainder by the square of the height, and the product by .5236. SEGUIER1A,... | |
 | Charles Hutton - 1822 - 616 pages
...the content of the cone ABI is = £ad3 X in =Jiad3 ; and by the similar cones ABI, «MI, is n double the height of the segment : then multiply the remainder by the square of the height, and the product by the decimal -5236, for the content. RULE II. To 3 times the square of the radius of the segment's... | |
 | James Mitchell - 1823 - 666 pages
...add tile square of its height; multiply the sum by the height, and the product by -5236. Or, 2dly, From three times the diameter of the sphere, subtract twice the height of the frustrum ; multiply the remainder by the square of the height, and the product by -5236. That is, in... | |
 | Anthony Nesbit - 1824 - 476 pages
...this sum multiplied by the height, and the product again by .5236, will give the solidity. RULE II. From three times the diameter of the sphere subtract twice the height of the segment; multiply the remainder by the square of the height, and that pro-i duct by .5236 for the solidity,... | |
| |
From three times the diameter of the sphere, take double the height of the segment ; then multiply the remainder by the square of the height, and... 
