An Introduction to Mensuration and Practical GeometryKimber & Sharpless, 1829 - 252 pages |
From inside the book
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Page 49
... square root . of the cube root . of equality . of proportion . REMARKS . 1. An angle in a semicircle is a right angle . 2. All angles in the same segment of a circle are equal . 3. Triangles that have all the three angles of the one ...
... square root . of the cube root . of equality . of proportion . REMARKS . 1. An angle in a semicircle is a right angle . 2. All angles in the same segment of a circle are equal . 3. Triangles that have all the three angles of the one ...
Page 56
... square root of the product will be the area required . EXAMPLES . 1. Required the area of the triangle ABC , whose three sides BC , CA , and AB are 24 , 36 , and 48 chains respec- tively . C A 24 + 36 + 48 108 Here- = 54 = sum of the ...
... square root of the product will be the area required . EXAMPLES . 1. Required the area of the triangle ABC , whose three sides BC , CA , and AB are 24 , 36 , and 48 chains respec- tively . C A 24 + 36 + 48 108 Here- = 54 = sum of the ...
Page 57
... square feet . 3. How many acres are there in a triangle whose three sides are 49.00 , 50.25 and 25.69 chains ? Ans ... root of the sum will be equal to the hypothenuse . 2. When the hypothenuse and one of the legs are given to find the other ...
... square feet . 3. How many acres are there in a triangle whose three sides are 49.00 , 50.25 and 25.69 chains ? Ans ... root of the sum will be equal to the hypothenuse . 2. When the hypothenuse and one of the legs are given to find the other ...
Page 59
... square root of the product will be the area . 2. Required the area of a trapezium whose diagonal is OF SUPERFICIES . 59 To find the sides of a right-angled triangle, To find the area of a trapezium,
... square root of the product will be the area . 2. Required the area of a trapezium whose diagonal is OF SUPERFICIES . 59 To find the sides of a right-angled triangle, To find the area of a trapezium,
Page 67
... square of the chord , add 33 times the square of the versed sine , † and reserve the number . To the square of the chord , add 4 times the square of the versed sine , and the square root or the sum will be twice the chord of half the ...
... square of the chord , add 33 times the square of the versed sine , † and reserve the number . To the square of the chord , add 4 times the square of the versed sine , and the square root or the sum will be twice the chord of half the ...
Common terms and phrases
9 inches ABCD adba altitude arch axis base Bisect breadth bung cask centre chord of half circle whose diameter circular circular segment circumference cone CONIC SECTIONS conjugate diameter convex surface cube curve cylinder Demon describe arcs cutting describe the arc diagonal distance divided draw the line ellipse equal EXAMPLES feet 6 inches feet 9 figure find the area find the solidity fluxion foot girt give the solidity given line greater end half the arc hexagon hyperbola hypothenuse length less abscissa less end linear side measure multiply the sum ordinate parabola parallel pentagon perpendicular PROBLEM prolate spheroid pyramid quotient radius rectangle regular polygon Required the area Required the solidity rhombus right line roof segment semicircle sine of half slant height SLIDING RULE solid content solidity required specific gravity sphere spheroid square root thickness transverse diameter trapezium ullage versed sine Whence wine gallons yard
Popular passages
Page ii - Co. of the said district, have deposited in this office the title of a book, the right whereof they claim as proprietors, in the words following, to wit : " Tadeuskund, the Last King of the Lenape. An Historical Tale." In conformity to the Act of the Congress of the United States...
Page 50 - The areas of circles are to each other as the squares of their diameters.
Page 19 - Parallel straight lines are such as are in the same plane, and which, being produced ever so far both ways, do not meet.
Page 125 - To find the solidity of a cylinder. RULE. — Multiply the area of the base by the altitude, and the product will be the solidity.
Page 21 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds.
Page 56 - Multiply the half sum and the three remainders continually together, and the square root of the product will be the area...
Page 54 - To find the area of a rectangular board, whose length is 12-^ feet, and breadth 9 inches. Ans. 9f feet.
Page 96 - As the conjugate diameter is to the transverse, So is the square root of the difference of the squares of the ordinate and semi-conjugate, To the distance between the ordinate and centre.
Page 16 - A sector is any part of a circle bounded by an arc, and two radii drawn to its extremities. A quadrant, or quarter of a circle...
Page 54 - To find the Area of a Triangle. Rule ] . Multiply the base by the perpendicular height, and half the product will be the area.