An Introduction to Mensuration and Practical Geometry |
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9 inches ABCD abscissa added altitude answer arch axis base body breadth called centre circle circular circumference cone contained cube cubic curve cutting cylinder Demon describe diameter difference dimensions distance divided double draw the line drawn ellipse equal EXAMPLES face feet 6 inches figure find the area find the solidity foot frustum girt given half the arc height hexagon hyperbola Join length mean measure method middle Multiply nearly Note opposite ordinate parallel pentagon perpendicular plane polygon practice PROBLEM proportional pyramid quotient radius regular Required the area right angles right line ring roof RULE segment side similar solidity sphere spheroid square root stands superficies supposing thickness third transverse diameter triangle twice versed sine wall Whence whole yard zone
Popular passages
Page ii - Co. of the said district, have deposited in this office the title of a book, the right whereof they claim as proprietors, in the words following, to wit : " Tadeuskund, the Last King of the Lenape. An Historical Tale." In conformity to the Act of the Congress of the United States...
Page 50 - The areas of circles are to each other as the squares of their diameters.
Page 19 - Parallel straight lines are such as are in the same plane, and which, being produced ever so far both ways, do not meet.
Page 125 - To find the solidity of a cylinder. RULE. — Multiply the area of the base by the altitude, and the product will be the solidity.
Page 21 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds.
Page 56 - Multiply the half sum and the three remainders continually together, and the square root of the product will be the area...
Page 54 - To find the area of a rectangular board, whose length is 12-^ feet, and breadth 9 inches. Ans. 9f feet.
Page 96 - As the conjugate diameter is to the transverse, So is the square root of the difference of the squares of the ordinate and semi-conjugate, To the distance between the ordinate and centre.
Page 16 - A sector is any part of a circle bounded by an arc, and two radii drawn to its extremities. A quadrant, or quarter of a circle...
Page 54 - To find the Area of a Triangle. Rule ] . Multiply the base by the perpendicular height, and half the product will be the area.