| 1801 - 446 pages
...1084-54, or l62t hothing remains, then will the last divisor be the greatest common measure required. 2. When there are more than two numbers, find the greatest common measure of two of them as before ; and. of that common measure and one of the other numbers ; and so on, through all the numbers to... | |
| Samuel Webber - 1808 - 466 pages
...divisor by the last remainder ; then will the last divisor be the greatest common measure required. 2. When there are more than two numbers, find the greatest common measure of two 6f them as before ; and of that common measure and ftie of the other numbers ; and so on through all... | |
| Charles Hutton - 1811 - 406 pages
...remainder ; and so on, dividing always the last divisor by the last remainder, till nothing remains ; so shall the last divisor of all be the greatest Common...common measure of two of them, as before; then do th« for that common measure and another of the numbers; and so on, through all the numbers; so will... | |
| Charles Hutton - 1812 - 620 pages
...remainder; and so on, dividing always the last divisor by the last remainder, till nothing remains ; so shall the last divisor of all be the greatest common...that common measure and another of the numbers ; and and so on, through all the numbers ; so will the greatest common measure last found be the answer.... | |
| Samuel Webber - 1812 - 260 pages
...divisor by the last remainder ; then will the last divisor be the greatest common measure required. 2. When there are more than two numbers, find the greatest common measure of two ofahem as before ; and of that common measure and one of the other numbers ; then will the greatest... | |
| Charles Hutton - 1816 - 610 pages
...remainder -, and sn on, dividing always the last divisor by the last remainder, till nothing remains ; so shall the last divisor of all be the greatest common...common measure of two of them, as before ; then do the dame for that common measure and another of the numbers -, and and so on. through all the numbers ;... | |
| Charles Hutton - 1822 - 616 pages
...remainder ; and so on, dividing always the last divisor by the last remainder, till nothing remains ; so shall the last divisor of all be the greatest common...common measure and another of the numbers ; and so, M, through all th« numbers ; 90 will the greatest common aaeature last found be the answer. 1. To... | |
| Nicolas Pike - 1832 - 538 pages
...remainder, till nothing remain, then will the last divisor be the greatest common measure required. II. When there are more than two numbers, find the greatest common measure of two of them, as before ; iheo, of that common measure and one of the other numbers, anj so on, through all the numbers, to... | |
| Nicolas Pike - 1822 - 562 pages
...the last divisor lie the greatest common mea^urt: required. II. When there are more than two number?, find the greatest common measure of two of them, as before ; then, of that common measure and one of the other number?, anil so on, through all the numbers, to the last... | |
| Charles Hutton - 1825 - 608 pages
...remainder ; and so on, dividing always the last divisor by the last remainder, till nothing remains : so shall the last divisor of all be the greatest common...measure of two of them, as before ; then do the same Tor that common measure and another of the numbers ; and so on. -i. through all the nmbers ; so wBl... | |
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