 | Anthony Birks, John Birks - 1766 - 640 pages
...without the firft is 5 The common difference - 3 The difference of the two extremes - 15 PROPOSITION I. The two extremes, and the number of terms, being given, to find the fum of all the feries, RULE, Multiply the fum of the two extremes into the number of terms, and divide... | |
 | Charles Vyse - 1785 - 350 pages
...continuing by the Increafc of 2 to 100 Places? PROPOSITION VII. The firft Term, common Difference, and Number of Terms being given, to find the Sum of all the Series. RULE. From tli? Product of the Number of Terms in the common Difference, fubtra'cl: the common... | |
 | 1801 - 446 pages
...sum of all the terms. . , PROBLEM I. , 1'te frit term, the last term, and the number of terms behtg given, to find the sum of all the terms. RULE.* Multiply the sum of the extremes by the number of terms,, and half the product will be the answer. EXAMPLES. * Suppose another series of... | |
 | Charles Vyse - 1806 - 342 pages
...continuing by the Increase of 2 to 100 Places? PROPOSITION VII. The first Term, common Difference, and Number of Terms being given, to find the Sum of all the Series. RULE. From the Product of the Number of Terms in tl# common Difference, subtract the common... | |
 | Samuel Webber - 1812 - 260 pages
...terms. 4. The common difference. 5. The sum of all the terms. PR0BLEM 1. Tke first term, the last term, and the number of terms being given, to find the sum...terms. RULE.* / Multiply the sum of the extremes by the number of terms, ami half the product will be die vinswer. EXAMPLES. 1. The first term of an Arithmetical... | |
 | Jeremiah Joyce - 1812 - 274 pages
...may be easily found. I. When the first term a, and the last .term z, and th« number of terms n, are given, to find the sum of all the terms, *. RULE. Multiply the sum of the extremes by the number ofte/mi, and divide by 2, the quotient is the ansu-er: or n a. + z X — = s. Ex. i . What... | |
 | Charles Butler - 1814 - 540 pages
...be found, as is shewn by the rules and examples following. 289. The least term, the greatest term, and the number of terms, being given, to find the sum of all the terms. RULE. Add the least and greatest terms together, multiply the sum by half the number of terms, and the product... | |
 | Nathan Daboll - 1815 - 250 pages
...first and last terms of which are culled the extremes.* PROBLEM I. The first term, the last term,.and the number of terms being given, to find the sum .of all the terms. *,:} series in progression includes Jive parts, viz. the, jfirsi term, last term, number of terms,... | |
 | Nathan Daboll - 1817 - 252 pages
...terms of the progression ; the first u.,d last terms of which are cal,ed The first term, the last term, and the number of terms being given, to find the sum of all the terms. *A series in progression includes Jive parts, rz'z. the first term, last term, number of terms, common... | |
 | Daniel Staniford - 1818 - 332 pages
...2=21-^-8 — 1=3 com. ditt'. of their ages. Youngest 21 4th . . 14' 7lh . 6th ... 5th . . 11 J PROPORTION II. The two extremes and the number of terms being...sum of all the terms. RULE. Multiply the sum of the two extremes by half the number of terms, the prodnct will be the sum of all the terms. EXAMPLES. :}.... | |
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PROBLEM I. The first term, the last term, and the number of terms being given, to find the sum of all the terms. 
