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" FIND the area of the sector having the same arc with the segment, by the last problem. Find also the area of the triangle, formed by the chord of the segment and the two radii of the sector. "
Mensuration and Practical Geometry: Containing Tables of Weights and ... - Page 84
by Charles Haynes Haswell - 1858 - 322 pages
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The Accomplished Tutor; Or, Complete System of Liberal Education ..., Volume 1

Thomas Hodson - 1806 - 502 pages
...AREA OF A SEGMENT Ot A CIRCLE. RULE. Find the area of the fe&or of the circle by the laflr Problem. Find the area of the triangle formed by the chord of the ftgment, aid the radius of the feftor. Then the turn of thefe two will be the anfwer, if thefegment...
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A Course of Mathematics in Two Volumes for the Use of Academies as Well as ...

Charles Hutton - 1807 - 464 pages
...I. FIND the area of the sector having the same arc with the segment, by the last problem. Find also the area of the triangle, formed by the chord of the segment and the two radii of the sector. Then add these two together for the answer, when the segment is greater than...
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Mathematics: Compiled from the Best Authors, and Intended to be ..., Volume 1

Samuel Webber - 1808 - 466 pages
...I. 1. Find the area of the sector, having the same arc with • the segment, by the last problem. 2. Find the area of the triangle, formed by the chord of the segment and the radii of the sector. S. Then the sum of these two will be the 'answer, when the segment is greater than a semicircle ; but...
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A Course of Mathematics ...: Composed for the Use of the Royal Military ...

Charles Hutton - 1811 - 442 pages
...FIND the area of the sector having the same arc •with the segment, by the last problem. Find also the area of the triangle, formed by the chord of the segment and the two radii of the sector. Then add these two together for the answer, when the segment is greater than...
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A Practical Application of the Principles of Geometry to the Mensuration of ...

Jeremiah Day - 1815 - 388 pages
...the area of a SEGMENT of a circle• 35. Find the area of the SECTOR which has the same art, and alto the area of the TRIANGLE formed by the chord of the segment and the radii of the sector. .'-\ •• . i^.' • ' Then, if the segment be LESS than a semi-circle, SUBTRACT the area of the...
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The complete measurer: or, The whole art of measuring, containing the ...

Thomas Keith - 1817 - 306 pages
...area of the sector, having the same arc as the segment. (Problem XV.) Kind the area of the triangK', formed by the chord of the segment and the radii of the sector. Then, if the segment be less than a semicircle, the difference of these two ar;'as will give the answer;...
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A Treatise on Practical Mensuration in Eight Parts ...

Anthony Nesbit - 1824 - 476 pages
...of a circle. RULE I. • f Find the area of the sector, having the Same arc as the segment ; also, find the area of the triangle formed by the chord of the segment and the radii of the sector ; then the difference of these areas, when the segment is less than a semicircle, or their sum, when...
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The Second [-fifth and Sixth] Part of A Course of Mathematics: Adapted to ...

Jeremiah Day - 1824 - 440 pages
...the area of a SEGMENT of a circle. 35. FIND THE AREA OF THE SECTOR WHICH HAS THE SAME ARC, AND ALSO THE AREA OF THE TRIANGLE FORMED BY THE CHORD OF THE SEGMENT AND THE RADII OF THE SECTOR. THEN, w THE SEGMENT BE LESS THAN A SEMI-CIRCLE, SUBTRACT THE AREA OF THE TRIANGLE FROM THE AREA OF...
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The Operative Mechanic, and British Machinist: Being a Practical ..., Volume 1

John Nicholson - 1825 - 838 pages
...Circle. Rule. Find the area of the sector having tbe same arc with the segment, by the last problem. Find the area of the triangle, formed by the chord of the segment and the two radii of the sector. Then the sum of these two will be tbe answer when the segment is greater than...
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A Compendium of Mechanics; Or; Text Book for Engineers, Mill-wrights ...

Robert Brunton - 1828 - 222 pages
...area of the sector, having the same arc with the segment, by the 2nd rule of last Problem. Find also the area of the triangle, formed by the chord of the segment and the two radii of MENSURAT10 the sector; then add these together for the answer, when the segment is greater...
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